I need help figuring out how to solve for x on certain triangles. I can solve it easily if it has two sides or two angles already stated, but I don't know what to do if it only has one angle and one side. I'll give a couple examples in the comments.

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I need help figuring out how to solve for x on certain triangles. I can solve it easily if it has two sides or two angles already stated, but I don't know what to do if it only has one angle and one side. I'll give a couple examples in the comments.

Mathematics
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|dw:1438880826360:dw|
X is the hypotenuse. I forgot to draw it.
your 3angle is 70

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Other answers:

Which third angle?
the top one
Can you show how you got it?
yeah
sum of all the angles of a triangle is 180 so your one angle is given 20 and the other one is 90 as it is a rt angled triangle so the other angle is -180 -(90+20)=70
Oh ok. So would I use Pythagorean triples to solve for x?
yeah
but one side is x and the other is 19 but you need to have data of another side
How do I do that? This is so confusing. Lol
probably the question is incorrect wait i'm checking
no the question is wrong you got to have two sides
It can't be wrong. I got it from my homework. Lol
any other info
Here are the choices: A. 55.6 B. 55.8 C. 6.7 D. 6.5
pls wait
nope there's surely some problem
I just don't think there is cuz there's other problems like this one but this one looked the simplest so I posted it.
ok
I think I found something in my book. If I mark the other unknown side as x, too, then I could do 2x squared = 19 squared and then find the square root
why will you mark the other side as x
did they tell you that they are equal
Hmmm..... good point lol
then also your answer is not coming i've calculated
did they tell you the area of the triangle
No, that's all it said besides the fact that it's not drawn to scale.
And to round to the nearest 10th
yeah theres something wrong wait i'm asking a frnd of mine
this has got to do with inverse sine function
Can you explain it, please?
\[\sin^{-1} (\frac{ 19 }{ x } = 20^{o}\]
hey i got it
its 55.8
you can try the options since its mcq
yeah
will you explain it to her
ok
I still don't know exactly how to solve it... Lol sorry, this stuff is confusing to me.
wait @Kailee1423 he'll explain it to you
you know \[\sin = \frac{ Opposite }{ Hypotenuse }\]
its a ratio of opposite and hypotenuse
Yeah, but how do you know which side is opposite?
|dw:1438883342515:dw|
thats how you know
you got to consider the 20 degree angle
then your sin 20=19/x sin 20 value is 0.34 so x=19/0.34=55.8
hey @Kailee1423 did you understand what we said
How did you get 0.34?
calculater sweety
just in a calculater try the value of sin 20
Oh ok. Why is it the sin of 20 instead of 19?
\[\sin 20 = 19/x\]\[0.342=19/x\]\[0.342x=19\]\[19/0.342=x\]
the angle is 20
because we always finf sin of an angle and not of a side
you dont sine the length only angle
yeah
now u understand
its actually 55.6
Thank you both! :) Sorry, my computer crashed.

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