I need help figuring out how to solve for x on certain triangles. I can solve it easily if it has two sides or two angles already stated, but I don't know what to do if it only has one angle and one side. I'll give a couple examples in the comments.

- Kailee1423

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- Kailee1423

|dw:1438880826360:dw|

- Kailee1423

X is the hypotenuse. I forgot to draw it.

- madhu.mukherjee.946

your 3angle is 70

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## More answers

- Kailee1423

Which third angle?

- madhu.mukherjee.946

the top one

- Kailee1423

Can you show how you got it?

- madhu.mukherjee.946

yeah

- madhu.mukherjee.946

sum of all the angles of a triangle is 180 so your one angle is given 20 and the other one is 90 as it is a rt angled triangle so the other angle is -180 -(90+20)=70

- Kailee1423

Oh ok. So would I use Pythagorean triples to solve for x?

- madhu.mukherjee.946

yeah

- madhu.mukherjee.946

but one side is x and the other is 19 but you need to have data of another side

- Kailee1423

How do I do that? This is so confusing. Lol

- madhu.mukherjee.946

probably the question is incorrect wait i'm checking

- madhu.mukherjee.946

no the question is wrong you got to have two sides

- Kailee1423

It can't be wrong. I got it from my homework. Lol

- madhu.mukherjee.946

any other info

- Kailee1423

Here are the choices:
A. 55.6
B. 55.8
C. 6.7
D. 6.5

- madhu.mukherjee.946

pls wait

- madhu.mukherjee.946

nope there's surely some problem

- Kailee1423

I just don't think there is cuz there's other problems like this one but this one looked the simplest so I posted it.

- madhu.mukherjee.946

ok

- Kailee1423

I think I found something in my book. If I mark the other unknown side as x, too, then I could do 2x squared = 19 squared and then find the square root

- madhu.mukherjee.946

why will you mark the other side as x

- madhu.mukherjee.946

did they tell you that they are equal

- Kailee1423

Hmmm..... good point lol

- madhu.mukherjee.946

then also your answer is not coming i've calculated

- madhu.mukherjee.946

did they tell you the area of the triangle

- Kailee1423

No, that's all it said besides the fact that it's not drawn to scale.

- Kailee1423

And to round to the nearest 10th

- madhu.mukherjee.946

yeah theres something wrong wait i'm asking a frnd of mine

- madhu.mukherjee.946

@saseal

- anonymous

this has got to do with inverse sine function

- Kailee1423

Can you explain it, please?

- anonymous

\[\sin^{-1} (\frac{ 19 }{ x } = 20^{o}\]

- madhu.mukherjee.946

hey i got it

- madhu.mukherjee.946

its 55.8

- anonymous

you can try the options since its mcq

- madhu.mukherjee.946

yeah

- madhu.mukherjee.946

will you explain it to her

- anonymous

ok

- Kailee1423

I still don't know exactly how to solve it... Lol sorry, this stuff is confusing to me.

- madhu.mukherjee.946

wait @Kailee1423 he'll explain it to you

- anonymous

you know
\[\sin = \frac{ Opposite }{ Hypotenuse }\]

- anonymous

its a ratio of opposite and hypotenuse

- Kailee1423

Yeah, but how do you know which side is opposite?

- anonymous

|dw:1438883342515:dw|

- anonymous

thats how you know

- madhu.mukherjee.946

you got to consider the 20 degree angle

- madhu.mukherjee.946

then your sin 20=19/x
sin 20 value is 0.34
so x=19/0.34=55.8

- madhu.mukherjee.946

hey @Kailee1423 did you understand what we said

- Kailee1423

How did you get 0.34?

- madhu.mukherjee.946

calculater sweety

- madhu.mukherjee.946

just in a calculater try the value of sin 20

- Kailee1423

Oh ok. Why is it the sin of 20 instead of 19?

- anonymous

\[\sin 20 = 19/x\]\[0.342=19/x\]\[0.342x=19\]\[19/0.342=x\]

- anonymous

the angle is 20

- madhu.mukherjee.946

because we always finf sin of an angle and not of a side

- anonymous

you dont sine the length only angle

- madhu.mukherjee.946

yeah

- madhu.mukherjee.946

now u understand

- anonymous

its actually 55.6

- Kailee1423

Thank you both! :) Sorry, my computer crashed.

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