cookie_monster
  • cookie_monster
Ok, this is a little crazy but...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
cookie_monster
  • cookie_monster
I had the task to create a literal equation with just symbols
cookie_monster
  • cookie_monster
# = & + %($@) This is the equation
cookie_monster
  • cookie_monster
Solve for $

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More answers

chrisdbest
  • chrisdbest
Oh, it's pretty simple actually
cookie_monster
  • cookie_monster
It is.
anonymous
  • anonymous
looks like censored swearing to me
chrisdbest
  • chrisdbest
# = BULL$HIT!!! :)
chrisdbest
  • chrisdbest
LOL :)
anonymous
  • anonymous
#=&+%$@ #-&=%$@
anonymous
  • anonymous
lol
anonymous
  • anonymous
you should know whats next
cookie_monster
  • cookie_monster
Lol ok, this is the answer I got: |dw:1438882479991:dw|
cookie_monster
  • cookie_monster
Correct or no?
anonymous
  • anonymous
no
anonymous
  • anonymous
|dw:1438882657717:dw|
cookie_monster
  • cookie_monster
So, |dw:1438882898947:dw|
anonymous
  • anonymous
yea
cookie_monster
  • cookie_monster
OK. Thank you!!!
cookie_monster
  • cookie_monster
@saseal
anonymous
  • anonymous
waddup?
anonymous
  • anonymous
waddup?
anonymous
  • anonymous
and yw
cookie_monster
  • cookie_monster
Do you mind helping me with another problem? All I need is an explanation. No direct answer.
anonymous
  • anonymous
ok
cookie_monster
  • cookie_monster
Solve for x: 2 over 5 (x - 4) = 2x.
anonymous
  • anonymous
like this?\[\frac{ 2 }{ 5(x-4) } = 2x\]
cookie_monster
  • cookie_monster
No, more like this |dw:1438884213727:dw|
anonymous
  • anonymous
\[\frac{ 2 }{ 5 }(x-4)=2x\]\[2(x-4)=10x\]\[x-4=5x\]\[-4=4x\]
anonymous
  • anonymous
you do the rest!
cookie_monster
  • cookie_monster
It would be -1.
cookie_monster
  • cookie_monster
Ok, so how do you get rid of the second x between step 3-4?
anonymous
  • anonymous
minus x from both sides

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