## cookie_monster one year ago Ok, this is a little crazy but...

I had the task to create a literal equation with just symbols

# = & + %($@) This is the equation 3. cookie_monster Solve for$

4. chrisdbest

Oh, it's pretty simple actually

It is.

6. anonymous

looks like censored swearing to me

7. chrisdbest

# = BULL$HIT!!! :) 8. chrisdbest LOL :) 9. anonymous #=&+%$@ #-&=%\$@

10. anonymous

lol

11. anonymous

you should know whats next

Lol ok, this is the answer I got: |dw:1438882479991:dw|

Correct or no?

14. anonymous

no

15. anonymous

|dw:1438882657717:dw|

So, |dw:1438882898947:dw|

17. anonymous

yea

OK. Thank you!!!

@saseal

20. anonymous

21. anonymous

22. anonymous

and yw

Do you mind helping me with another problem? All I need is an explanation. No direct answer.

24. anonymous

ok

Solve for x: 2 over 5 (x - 4) = 2x.

26. anonymous

like this?$\frac{ 2 }{ 5(x-4) } = 2x$

No, more like this |dw:1438884213727:dw|

28. anonymous

$\frac{ 2 }{ 5 }(x-4)=2x$$2(x-4)=10x$$x-4=5x$$-4=4x$

29. anonymous

you do the rest!

It would be -1.

Ok, so how do you get rid of the second x between step 3-4?

32. anonymous

minus x from both sides