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plz help me id understand this trickery at all
okay pick a rational function and tell me
what is a rational function lol
Consider where the fraction is not defined. When you have a fraction, what is that famous number you cannot divide by?
0 lol i think or im stupid lol
You aren't stupid. And that is an awesome answer because it is true. So when is your fraction's bottom zero? For what value of x, do you have x-1 is zero?
good question idk how to answer them
what number can you take away 1 from and have zero?
is 5-1 zero? is 2-1 zero?
no 1-1 is 0
yes x-1=0 has solution x=1 you could have also just added 1 on both sides
true ok i get it somewhat now
ok so if i was to answer this question then how would i phrase this
x=1 is your vertical asymptote though if there was a factor of x-1 on top then it could possibly be a hole (but you do not have that here) that is f(x)=(x-1)/(x-1) has a hole at x=1 (not a vertical asymptote) that is f(x)=x(x-1)/(x-1) also has a hole at x=1 but g(x)=(x-1)/(x-1)^2 has a vertical asympote at x=1 since it has more (x-1)'s on bottom then on top
i hate math so bad lol good thing this is my lsast math class lol thnx for your help
thank you to dan