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anonymous
 one year ago
\[\frac{ 3 }{ x3}=\frac{ x }{ x3 }\frac{ 3 }{ 2 }x \]
\[\frac{ 3 }{ x3 }=\frac{ 2x3x(x3) }{ 2\left( x3 \right) }\]
multiply both sides by 2(x3)
\[6=2x3x^2+9x,3x^211x+6=0\]
3x^29x2x+6=0
3x(x3)2(x3)=0
(x3)(3x2)=0
\[x3=0 ~or~ x=3~is~an~extraneous~ root.\]
or 3x2=0
calculate x
anonymous
 one year ago
\[\frac{ 3 }{ x3}=\frac{ x }{ x3 }\frac{ 3 }{ 2 }x \] \[\frac{ 3 }{ x3 }=\frac{ 2x3x(x3) }{ 2\left( x3 \right) }\] multiply both sides by 2(x3) \[6=2x3x^2+9x,3x^211x+6=0\] 3x^29x2x+6=0 3x(x3)2(x3)=0 (x3)(3x2)=0 \[x3=0 ~or~ x=3~is~an~extraneous~ root.\] or 3x2=0 calculate x

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