What is common to both terms?
largest even divisor of -2 and 6 ?
Right, but for the term with the largest exponent on X, you usually want it to be Positive, so , i would pull out a -2
(-2) * (x^3 - 3x^2)
−x(2x2 − 6x) 2x(−x2 + 3x) −2x2(x − 3) Prime
those are the coices
For the variable part, if every term has the common variable, you can pull out the smallest power
−x(2x^2 − 6x) 2x(−x^2 + 3x) −2x^2(x − 3) Prime
Pull out an x^2, and divide the remaining by that
(-2x^2)(x - 3)
you can check by distributing back to see if you get the original problem
wat do u mean by thatok 1 sec
ok 1 sec
ok thnks bro