anonymous
  • anonymous
MEDAL/FAN There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45 homes. Each year, 3 new homes are built in Neighborhood B. Part C: After approximately how many years is the number of homes in Neighborhood A and Neighborhood B the same? Justify your answer mathematically.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@Kainui @mathway
DanJS
  • DanJS
Was part A and B to come up with the equations to model both those situations?
anonymous
  • anonymous
Part A:Neighborhood A:y=30(1.2)^x Neighborhood B: y=40+3x Part B: I just substitute x for 5. Neighborhood A's work: y=30(1.2)^5 y=30*2.48832 y=74.6494, or around 75 houses. Neighborhood B's work: y=40+3*5 y=40+15 y=55, so 55 houses @DanJS my answers^

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

DanJS
  • DanJS
ok...
DanJS
  • DanJS
Part C wants you to figure the years X, when both are equal # houses
DanJS
  • DanJS
30(1.2)^x = 40 + 3x
anonymous
  • anonymous
I know but I dont know what number to start at
DanJS
  • DanJS
Oh, you have 40 for neighborhood B, it is 45 30(1.2)^x = 45 + 3x
DanJS
  • DanJS
So recalculate part B for that one
anonymous
  • anonymous
you sure? Okay so final houses=60
DanJS
  • DanJS
"Neighborhood B has 45 homes. Each year, 3 new homes are built ", less the prob is typed wrong
anonymous
  • anonymous
its right; 45
anonymous
  • anonymous
/?What number should I START with
anonymous
  • anonymous
20% of 30 is 6 so you could just use process of elimination. 3*5=15 15+45=60 5*6=30 30+30=60 so after 5 years they will be the same
anonymous
  • anonymous
30(1.2)^5 does not equal 60
anonymous
  • anonymous
@david422
anonymous
  • anonymous
where did you get 30(1.2)^5??
anonymous
  • anonymous
y=30(1.2)^x
anonymous
  • anonymous
The equation from part one
anonymous
  • anonymous
@DanJS
anonymous
  • anonymous
idk i just went off what your initial question was
anonymous
  • anonymous
well the equations are: Neighborhood A:y=30(1.2)^x Neighborhood B: y=45+3x
anonymous
  • anonymous
@DanJS
anonymous
  • anonymous
@ali2x2
anonymous
  • anonymous
@Kainui
anonymous
  • anonymous
@Afrodiddle @zepdrix
DanJS
  • DanJS
sorry back, here is the graph
DanJS
  • DanJS
the intersection is the point you need
anonymous
  • anonymous
okay so when x=3.32, the two points intersect
anonymous
  • anonymous
3.321 i meant
DanJS
  • DanJS
yes, when 3.32 years have passed , both have same number of houses at near 55
anonymous
  • anonymous
okay, thanks!
DanJS
  • DanJS
i just asked a question about that form of equation...
DanJS
  • DanJS
welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.