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anonymous
 one year ago
MEDAL/FAN
There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45 homes. Each year, 3 new homes are built in Neighborhood B.
Part C: After approximately how many years is the number of homes in Neighborhood A and Neighborhood B the same? Justify your answer mathematically.
anonymous
 one year ago
MEDAL/FAN There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45 homes. Each year, 3 new homes are built in Neighborhood B. Part C: After approximately how many years is the number of homes in Neighborhood A and Neighborhood B the same? Justify your answer mathematically.

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DanJS
 one year ago
Best ResponseYou've already chosen the best response.1Was part A and B to come up with the equations to model both those situations?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part A:Neighborhood A:y=30(1.2)^x Neighborhood B: y=40+3x Part B: I just substitute x for 5. Neighborhood A's work: y=30(1.2)^5 y=30*2.48832 y=74.6494, or around 75 houses. Neighborhood B's work: y=40+3*5 y=40+15 y=55, so 55 houses @DanJS my answers^

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1Part C wants you to figure the years X, when both are equal # houses

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know but I dont know what number to start at

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1Oh, you have 40 for neighborhood B, it is 45 30(1.2)^x = 45 + 3x

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1So recalculate part B for that one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you sure? Okay so final houses=60

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1"Neighborhood B has 45 homes. Each year, 3 new homes are built ", less the prob is typed wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0/?What number should I START with

anonymous
 one year ago
Best ResponseYou've already chosen the best response.020% of 30 is 6 so you could just use process of elimination. 3*5=15 15+45=60 5*6=30 30+30=60 so after 5 years they will be the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.030(1.2)^5 does not equal 60

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0where did you get 30(1.2)^5??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The equation from part one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk i just went off what your initial question was

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well the equations are: Neighborhood A:y=30(1.2)^x Neighborhood B: y=45+3x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Afrodiddle @zepdrix

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1sorry back, here is the graph

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1the intersection is the point you need

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so when x=3.32, the two points intersect

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1yes, when 3.32 years have passed , both have same number of houses at near 55

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1i just asked a question about that form of equation...
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