anonymous
  • anonymous
Which of the following is not a way to represent the solution of the inequality 3(2x - 1) greater than or equal to 4(2x - 3) - 3? A. x less than or equal to B. x greater than or equal to C. A number line with closed circle on 6 shading to the left. D. A number line with closed on 6 shading to the right.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
To solve the inequality, simplify the expressions first 3(2x - 1) => 4(2x - 3) - 3
campbell_st
  • campbell_st
1st thing to do is solve the inequality and see what you have as a solution
anonymous
  • anonymous
Distribute 3 to 2x - 1. On the right side of the inequality, distribute 4 to 2x - 3.

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anonymous
  • anonymous
Can I do distributed property first?
anonymous
  • anonymous
6x-1=>8x-12-12?
anonymous
  • anonymous
Do like terms now ?
anonymous
  • anonymous
Simplify the right side of the inequality further!
anonymous
  • anonymous
6x-1=>8x?
anonymous
  • anonymous
Also, on the right side, it's -12 - 3.
anonymous
  • anonymous
I canceled 12 out
anonymous
  • anonymous
So that turns into 8x - 15.
anonymous
  • anonymous
So 6x-1=>8x-15? Now combine like terms right?
anonymous
  • anonymous
It's also 6x-3. -1 * 3 = 3. The equation now looks like 6x - 3 => 8x - 15 Now, solve the inequality by isolating x. Hint! Subtract 6x from both sides of the equation.
anonymous
  • anonymous
2x-3=>-15 add 3 to both sides right? and I would get -12?
anonymous
  • anonymous
Okay so the equation is −3≥8x−15−6x. It simplifies into −3≥2x−15. Now, add 15 to both sides to get 2x by itself.
anonymous
  • anonymous
\[2x \ge 12 \]
anonymous
  • anonymous
Thanks you I got \[x \le 6\]
anonymous
  • anonymous
Yep that's correct

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