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anonymous

  • one year ago

Which of the following is not a way to represent the solution of the inequality 3(2x - 1) greater than or equal to 4(2x - 3) - 3? A. x less than or equal to B. x greater than or equal to C. A number line with closed circle on 6 shading to the left. D. A number line with closed on 6 shading to the right.

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  1. anonymous
    • one year ago
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    To solve the inequality, simplify the expressions first 3(2x - 1) => 4(2x - 3) - 3

  2. campbell_st
    • one year ago
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    1st thing to do is solve the inequality and see what you have as a solution

  3. anonymous
    • one year ago
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    Distribute 3 to 2x - 1. On the right side of the inequality, distribute 4 to 2x - 3.

  4. anonymous
    • one year ago
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    Can I do distributed property first?

  5. anonymous
    • one year ago
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    6x-1=>8x-12-12?

  6. anonymous
    • one year ago
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    Do like terms now ?

  7. anonymous
    • one year ago
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    Simplify the right side of the inequality further!

  8. anonymous
    • one year ago
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    6x-1=>8x?

  9. anonymous
    • one year ago
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    Also, on the right side, it's -12 - 3.

  10. anonymous
    • one year ago
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    I canceled 12 out

  11. anonymous
    • one year ago
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    So that turns into 8x - 15.

  12. anonymous
    • one year ago
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    So 6x-1=>8x-15? Now combine like terms right?

  13. anonymous
    • one year ago
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    It's also 6x-3. -1 * 3 = 3. The equation now looks like 6x - 3 => 8x - 15 Now, solve the inequality by isolating x. Hint! Subtract 6x from both sides of the equation.

  14. anonymous
    • one year ago
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    2x-3=>-15 add 3 to both sides right? and I would get -12?

  15. anonymous
    • one year ago
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    Okay so the equation is −3≥8x−15−6x. It simplifies into −3≥2x−15. Now, add 15 to both sides to get 2x by itself.

  16. anonymous
    • one year ago
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    \[2x \ge 12 \]

  17. anonymous
    • one year ago
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    Thanks you I got \[x \le 6\]

  18. anonymous
    • one year ago
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    Yep that's correct

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