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For the inverse variation equation xy = k, what is the constant of variation, k, when x = –3 and y = –2

- anonymous

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- anonymous

–6
-2/3
3/2
6

- skullpatrol

Any ideas?

- anonymous

-2/3 would be my guess

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- skullpatrol

Guessing randomly doesn't work in math :-)
Please give a reason.

- anonymous

because usually its x/y right? so the inverse would be y/x

- skullpatrol

You are correct that "usually" you see expressions like x/y in class
and the inverse of x/y is y/x,
but that is not what this question is asking for.

- anonymous

So its 6?

- anonymous

no that doesnt make sense

- skullpatrol

Yes. 6 is correct :-)

- skullpatrol

For the inverse variation equation xy = k,
what is the constant of variation, k,
when x = –3 and y = –2
x * y = k
-3 (-2) = 6

- anonymous

Thank you! Can you help me with another one?

- skullpatrol

I can try.

- anonymous

The inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y.
y=3x10^8/x
What is the wavelength for radio waves with frequency 3 × 10^9?
1 × 10^–1 m
3 × 10^–1 m
3 × 10^17 m
9 × 10^17 m

- skullpatrol

Any ideas?

- skullpatrol

|dw:1438892577073:dw|

- anonymous

so find y=3x10^8/x

- skullpatrol

Read the problem carefully.
Decide what unknown number is being asked for.

- anonymous

3x10^9?

- skullpatrol

that's not an answer choice

- anonymous

I still dont understand

- skullpatrol

what is the question asking for?

- anonymous

What is the wavelength for radio waves with frequency 3 × 10^9

- skullpatrol

Good, where is the wavelength in the formula they gave you?

- anonymous

wavelength is x and frequency is y

- skullpatrol

so they want you to find x, right?

- anonymous

yes

- skullpatrol

|dw:1438893690522:dw|

- skullpatrol

|dw:1438893825211:dw|

- skullpatrol

Ok so far?

- anonymous

yes

- skullpatrol

Do you know how to solve for x?

- anonymous

I plugged it in but it came out to be 1

- skullpatrol

plugged what in?

- anonymous

is it A?

- anonymous

(3*10^9)=(3*10^8)/x

- anonymous

x=1/10

- skullpatrol

Correct :-)

- anonymous

Thank you!

- skullpatrol

Thanks for trying :D

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