A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

bye

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    line R: 2x+2y=18 subtract 2x from both sides and you'll get 2y=-2x+18 and then divide it by 2 and you'll get y=-x+9 line M: x+y=9 subtract x from both sides and you'll get y=-x+9 and I think its C

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Solve by using the process of elimination. To get the second equation to equal the first equation, multiply it by 2. 2(x+y=9) = 2x+2y=18 2x+2y=18 = 2x+2y=18

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    These equations both equal the same line. Do they have one solution, no solution, or infinitely many solutions?

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes.

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You're welcome

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    np

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.