anonymous
  • anonymous
Figure ABCDE has vertices A(−2, 3), B(2, 3), C(5, −2), D(0, −4), and E(−2, −2). Plot the points on your own coordinate grid and connect the points in alphabetical order. Decompose Figure ABCDE into rectangles and triangles. Part A: How many triangles and rectangles did you make? (1 point) Part B: Use Figure ABCDE created on your coordinate grid to find the lengths, in units, of Sides AB and AE. (4 points) Part C: What is the area of Figure ABCDE? Show your work. (5 points)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@DarkMoonZ
anonymous
  • anonymous
@Michele_Laino
anonymous
  • anonymous
How would i do this? im confused on how to solve this.

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More answers

Michele_Laino
  • Michele_Laino
I'm doing the drawing of your points...
anonymous
  • anonymous
Ok should i get graph paper?
Michele_Laino
  • Michele_Laino
I think that it is better
anonymous
  • anonymous
i can't find it nvm
Michele_Laino
  • Michele_Laino
|dw:1438892480757:dw|
Michele_Laino
  • Michele_Laino
next step: |dw:1438892648200:dw|
Michele_Laino
  • Michele_Laino
next step: |dw:1438892711601:dw|
Michele_Laino
  • Michele_Laino
I got two rectangles and two triangles
anonymous
  • anonymous
Yes it looks really good
anonymous
  • anonymous
to find the length of in units of Sides AB and AE how would i do that i keep forgetting what to do
Michele_Laino
  • Michele_Laino
you have to compute the difference between the x-coordinates or y.coordinates. For example: \[\Large \begin{gathered} AB = 2 - \left( { - 2} \right) = ... \hfill \\ AE = 3 - \left( { - 2} \right) = ... \hfill \\ \end{gathered} \]
Michele_Laino
  • Michele_Laino
the distance has to be always a positive number
anonymous
  • anonymous
4
Michele_Laino
  • Michele_Laino
AB=4, ok! and AE=...?
anonymous
  • anonymous
i got 5
Michele_Laino
  • Michele_Laino
that's right!
anonymous
  • anonymous
Whoop whoop! (:
Michele_Laino
  • Michele_Laino
the area of our polygon is given by the sum of the areas of the two rectangles and two triangles
anonymous
  • anonymous
So i do what i just did for all of them now for c?
Michele_Laino
  • Michele_Laino
|dw:1438893214246:dw|
Michele_Laino
  • Michele_Laino
area of rectangle ABPQ= PQ*AP=4* 3=...? being PQ= AB= 4,a nd AP = 3-0=3
anonymous
  • anonymous
12
Michele_Laino
  • Michele_Laino
ok! next: area of rectangle PQER: ER*EP= 4*2=... being ER=AB=4 EP=0-(-2)=2
anonymous
  • anonymous
8
Michele_Laino
  • Michele_Laino
correct!
Michele_Laino
  • Michele_Laino
nexT: area of triangle ECD= EC*HD=...? being EC=5-(-2)=7 HD=-2-(-4)=2 |dw:1438893545943:dw|
Michele_Laino
  • Michele_Laino
next*
Michele_Laino
  • Michele_Laino
oops... area of triangle ECD= (EC*HD)/2=...?
anonymous
  • anonymous
11
anonymous
  • anonymous
and
Michele_Laino
  • Michele_Laino
we have: area of triangle ECD= EC*HD=(7*2)/2=...?
anonymous
  • anonymous
7
Michele_Laino
  • Michele_Laino
correct!
Michele_Laino
  • Michele_Laino
next step: are of triangle BRC= BR*RC/2=...? being: BR=3-(-2)=5 RC=5-2=3
anonymous
  • anonymous
7.5? is it 5x3x1/2?
Michele_Laino
  • Michele_Laino
that's right!
anonymous
  • anonymous
yay!
Michele_Laino
  • Michele_Laino
so area of our polygon is: 12+8+7+7.5=...?
anonymous
  • anonymous
34.5!!
Michele_Laino
  • Michele_Laino
yes! correct!
anonymous
  • anonymous
Yes im so happy when you help me i understand it better.
Michele_Laino
  • Michele_Laino
thanks! :)

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