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anonymous

  • one year ago

Figure ABCDE has vertices A(−2, 3), B(2, 3), C(5, −2), D(0, −4), and E(−2, −2). Plot the points on your own coordinate grid and connect the points in alphabetical order. Decompose Figure ABCDE into rectangles and triangles. Part A: How many triangles and rectangles did you make? (1 point) Part B: Use Figure ABCDE created on your coordinate grid to find the lengths, in units, of Sides AB and AE. (4 points) Part C: What is the area of Figure ABCDE? Show your work. (5 points)

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  1. anonymous
    • one year ago
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    @DarkMoonZ

  2. anonymous
    • one year ago
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    @Michele_Laino

  3. anonymous
    • one year ago
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    How would i do this? im confused on how to solve this.

  4. Michele_Laino
    • one year ago
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    I'm doing the drawing of your points...

  5. anonymous
    • one year ago
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    Ok should i get graph paper?

  6. Michele_Laino
    • one year ago
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    I think that it is better

  7. anonymous
    • one year ago
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    i can't find it nvm

  8. Michele_Laino
    • one year ago
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    |dw:1438892480757:dw|

  9. Michele_Laino
    • one year ago
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    next step: |dw:1438892648200:dw|

  10. Michele_Laino
    • one year ago
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    next step: |dw:1438892711601:dw|

  11. Michele_Laino
    • one year ago
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    I got two rectangles and two triangles

  12. anonymous
    • one year ago
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    Yes it looks really good

  13. anonymous
    • one year ago
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    to find the length of in units of Sides AB and AE how would i do that i keep forgetting what to do

  14. Michele_Laino
    • one year ago
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    you have to compute the difference between the x-coordinates or y.coordinates. For example: \[\Large \begin{gathered} AB = 2 - \left( { - 2} \right) = ... \hfill \\ AE = 3 - \left( { - 2} \right) = ... \hfill \\ \end{gathered} \]

  15. Michele_Laino
    • one year ago
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    the distance has to be always a positive number

  16. anonymous
    • one year ago
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    4

  17. Michele_Laino
    • one year ago
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    AB=4, ok! and AE=...?

  18. anonymous
    • one year ago
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    i got 5

  19. Michele_Laino
    • one year ago
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    that's right!

  20. anonymous
    • one year ago
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    Whoop whoop! (:

  21. Michele_Laino
    • one year ago
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    the area of our polygon is given by the sum of the areas of the two rectangles and two triangles

  22. anonymous
    • one year ago
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    So i do what i just did for all of them now for c?

  23. Michele_Laino
    • one year ago
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    |dw:1438893214246:dw|

  24. Michele_Laino
    • one year ago
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    area of rectangle ABPQ= PQ*AP=4* 3=...? being PQ= AB= 4,a nd AP = 3-0=3

  25. anonymous
    • one year ago
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    12

  26. Michele_Laino
    • one year ago
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    ok! next: area of rectangle PQER: ER*EP= 4*2=... being ER=AB=4 EP=0-(-2)=2

  27. anonymous
    • one year ago
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    8

  28. Michele_Laino
    • one year ago
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    correct!

  29. Michele_Laino
    • one year ago
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    nexT: area of triangle ECD= EC*HD=...? being EC=5-(-2)=7 HD=-2-(-4)=2 |dw:1438893545943:dw|

  30. Michele_Laino
    • one year ago
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    next*

  31. Michele_Laino
    • one year ago
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    oops... area of triangle ECD= (EC*HD)/2=...?

  32. anonymous
    • one year ago
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    11

  33. anonymous
    • one year ago
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    and

  34. Michele_Laino
    • one year ago
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    we have: area of triangle ECD= EC*HD=(7*2)/2=...?

  35. anonymous
    • one year ago
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    7

  36. Michele_Laino
    • one year ago
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    correct!

  37. Michele_Laino
    • one year ago
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    next step: are of triangle BRC= BR*RC/2=...? being: BR=3-(-2)=5 RC=5-2=3

  38. anonymous
    • one year ago
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    7.5? is it 5x3x1/2?

  39. Michele_Laino
    • one year ago
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    that's right!

  40. anonymous
    • one year ago
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    yay!

  41. Michele_Laino
    • one year ago
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    so area of our polygon is: 12+8+7+7.5=...?

  42. anonymous
    • one year ago
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    34.5!!

  43. Michele_Laino
    • one year ago
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    yes! correct!

  44. anonymous
    • one year ago
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    Yes im so happy when you help me i understand it better.

  45. Michele_Laino
    • one year ago
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    thanks! :)

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