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anonymous
 one year ago
Using the completingthesquare method, rewrite f(x) = x2 + 10x + 7 in vertex form
anonymous
 one year ago
Using the completingthesquare method, rewrite f(x) = x2 + 10x + 7 in vertex form

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 @dan815 @Kainui @Michele_Laino @DanJS

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0hint: we can add and subtract 25, so we can write this: \[\Large \begin{gathered} f\left( x \right) = {x^2} + 10x + 7 = \hfill \\ \\ = {x^2} + 10x + 25  25 + 7 \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What does that do? confused

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0we have: \[\Large {x^2} + 10x + 25 = {\left( {x + 5} \right)^2}\] am I right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(x)=(x+5)^218 f(x)=(x+10)^2+25 f(x)=(x+5)^2+7 f(x)=(x+5)^2 Those are my options btw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0so, what is the right option? Please look at my second hint

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0sorry, it is not B

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0hint: \[\Large \begin{gathered} f\left( x \right) = {x^2} + 10x + 7 = \hfill \\ \hfill \\ = {x^2} + 10x + 25  25 + 7 = \hfill \\ \hfill \\ = {x^2} + 10x + 25  18 \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0please keep in mind that: \[\Large {x^2} + 10x + 25 = {\left( {x + 5} \right)^2}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0yes! that's right!
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