anonymous
  • anonymous
Using the completing-the-square method, rewrite f(x) = x2 + 10x + 7 in vertex form
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@ganeshie8 @dan815 @Kainui @Michele_Laino @DanJS
Michele_Laino
  • Michele_Laino
hint: we can add and subtract 25, so we can write this: \[\Large \begin{gathered} f\left( x \right) = {x^2} + 10x + 7 = \hfill \\ \\ = {x^2} + 10x + 25 - 25 + 7 \hfill \\ \end{gathered} \]
anonymous
  • anonymous
What does that do? confused

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Michele_Laino
  • Michele_Laino
we have: \[\Large {x^2} + 10x + 25 = {\left( {x + 5} \right)^2}\] am I right?
anonymous
  • anonymous
f(x)=(x+5)^2-18 f(x)=(x+10)^2+25 f(x)=(x+5)^2+7 f(x)=(x+5)^2 Those are my options btw
Michele_Laino
  • Michele_Laino
so, what is the right option? Please look at my second hint
anonymous
  • anonymous
I'd say B
Michele_Laino
  • Michele_Laino
sorry, it is not B
Michele_Laino
  • Michele_Laino
hint: \[\Large \begin{gathered} f\left( x \right) = {x^2} + 10x + 7 = \hfill \\ \hfill \\ = {x^2} + 10x + 25 - 25 + 7 = \hfill \\ \hfill \\ = {x^2} + 10x + 25 - 18 \hfill \\ \end{gathered} \]
Michele_Laino
  • Michele_Laino
please keep in mind that: \[\Large {x^2} + 10x + 25 = {\left( {x + 5} \right)^2}\]
anonymous
  • anonymous
So its A?
Michele_Laino
  • Michele_Laino
yes! that's right!
anonymous
  • anonymous
Thank you!!
Michele_Laino
  • Michele_Laino
:)

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