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anonymous
 one year ago
Rewrite f(x) = –(x + 3)2 − 1 from vertex form to standard form
anonymous
 one year ago
Rewrite f(x) = –(x + 3)2 − 1 from vertex form to standard form

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0vertex form: y=a(x  h)^2+k Standard form: y = ax^2 + bx + c

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i need to plug in the numbes?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so first thing you do is distribute the (x + 3)^2 expression. After you've distributed, multiply the expression with 1. Then, subtract 1.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, I think I'm explaining in a really crappy way right now. Let me reword it. So, take your vertex form expression. –1*(x + 3)^2 − 1. The first thing you want to do is simplify the term in parenthesis. Which is (x + 3)^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0F(x)=x^26x10 f(x)=x^26x+8 f(x)=x^26x8 f(x)=x^28 Those are my choices btw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so first distribute. (x + 3)(x + 3).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Plug it into the remaining parts of the equation! The equation is now –1*X^2+6x+9 − 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Simplify the rest of the equation. –1*X^2+6x+9 − 1 Multiply (X^2+6x+9) by 1. After you've received your answer, subtract 1 from it. That is your equation in standard form!
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