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anonymous
 one year ago
Find the values of x so that the series below converges. (((x+8)^(n))/(2^n)) please help find the interval. goes to INF and n=0
anonymous
 one year ago
Find the values of x so that the series below converges. (((x+8)^(n))/(2^n)) please help find the interval. goes to INF and n=0

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thomas5267
 one year ago
Best ResponseYou've already chosen the best response.0Is this the equation? \[ a_n=\frac{(x+8)^n}{2^n} \]

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.0What is the required limit?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm looking to find the values of x so that the series below converges. (the interval it does

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0does that makes sense can u help?

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.0So the question is find x such that: \[ \lim_{n\to0}\frac{(x+8)^n}{2^n}=\infty \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no it has the simga logo in front of the fraction with a INF aboe th sigma and a n=0 below

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=0}^{INF}\]

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.0Find such x such that: \[ \sum_{n=0}^\infty\frac{(x+8)^n}{2^n}=\infty \]
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