## anonymous one year ago Find the values of x so that the series below converges. (((x+8)^(n))/(2^n)) please help find the interval. goes to INF and n=0

1. thomas5267

Is this the equation? $a_n=\frac{(x+8)^n}{2^n}$

2. anonymous

yes

3. thomas5267

What is the required limit?

4. anonymous

I'm looking to find the values of x so that the series below converges. (the interval it does

5. anonymous

limit is n=0

6. anonymous

to INF

7. anonymous

does that makes sense can u help?

8. thomas5267

So the question is find x such that: $\lim_{n\to0}\frac{(x+8)^n}{2^n}=\infty$

9. anonymous

no it has the simga logo in front of the fraction with a INF aboe th sigma and a n=0 below

10. anonymous

$\sum_{n=0}^{INF}$

11. thomas5267

Find such x such that: $\sum_{n=0}^\infty\frac{(x+8)^n}{2^n}=\infty$