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anonymous

  • one year ago

Which inequality matches the graph? X, Y graph. X range is negative 10 to 10, and Y range is negative 10 to 10. Dashed line on graph has positive slope and runs through negative 10, negative 9 and negative 1, negative 3 and 8, 3. Above line is shaded. −2x + 3y > 7 2x − 3y < 7 −3x + 2y ≥ 7 3x − 2y ≤ 7

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  1. anonymous
    • one year ago
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  2. DanJS
    • one year ago
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    you can use 2 points (-10 , -9) and (-1 , -3) to calculate the slope, and use the point-slope form to get your equation for the line

  3. DanJS
    • one year ago
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    you can rearrange that to the standard form as in the choices

  4. DanJS
    • one year ago
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    y is greater than, (dotted line and shaded above)

  5. anonymous
    • one year ago
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    What? @DanJS

  6. DanJS
    • one year ago
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    slope = m = (change in y value)/(change in x value) = [-3 - (-9)] / [-1 - (-10)] m = 6/9 = 2/3

  7. anonymous
    • one year ago
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    okay so

  8. DanJS
    • one year ago
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    Using that slope m=2/3 and any point on the line, (x1,y1)= (-1, -3) Point-Slope Form: y - y1 = m*(x-x1)

  9. anonymous
    • one year ago
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    okay

  10. DanJS
    • one year ago
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    y - (-3) = (2/3)*(x - (-1))

  11. anonymous
    • one year ago
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    mhhmm

  12. DanJS
    • one year ago
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    y + 3 = (2/3)x + (2/3) y = (2/3)*x - (7/3)

  13. anonymous
    • one year ago
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    okkk

  14. DanJS
    • one year ago
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    From the graph, it is a dotted line meaning it is > or < not equal to, and shaded above means greater, so y is greater than y > (2/3)*x - (7/3)

  15. DanJS
    • one year ago
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    that is the inequality, just have to put it into the standard form

  16. anonymous
    • one year ago
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    A?

  17. anonymous
    • one year ago
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    B? LOL i am so stupid

  18. DanJS
    • one year ago
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    multiply everything by 3 3y > 2x - 7 -2x + 3y > -7 yep

  19. DanJS
    • one year ago
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    yeah they just multiplied everything by -1

  20. DanJS
    • one year ago
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    which flips the sign th eothe rway 2x - 3y < 7

  21. anonymous
    • one year ago
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    so b? @DanJS

  22. anonymous
    • one year ago
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    @DanJS Was this B?

  23. anonymous
    • one year ago
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    @DanJS please @heretohelpalways

  24. anonymous
    • one year ago
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    is it B?

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