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anonymous
 one year ago
Find the length of the curve x=1+9t^2, y=3+6t^3, (0<x<6) PLEASE HELP
anonymous
 one year ago
Find the length of the curve x=1+9t^2, y=3+6t^3, (0<x<6) PLEASE HELP

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freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[\text{ we have to use this } \int\limits_{a(t)}^{b(t)} \sqrt{(x')^2+(y')^2} dt \text{ or try to use } \\ \int\limits_{a(x)}^{b(x)} \sqrt{ 1+(y')^2} dx\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.2do you want to try to write y in terms of x?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2i'm asking that because if we try to write the x limits in terms of t limits we will end up with 4 numbers 2 of them being imaginary

freckles
 one year ago
Best ResponseYou've already chosen the best response.2this question is a tad weird for me it is 0<x<6 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea it says Find the length of the curve X=1+9t^2, and y+3+6t^3 (0 <t<6)

freckles
 one year ago
Best ResponseYou've already chosen the best response.2oh that makes the problem tons easier you said 0<x<6

freckles
 one year ago
Best ResponseYou've already chosen the best response.2then just use that one parametric formula I gave you

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[\int\limits\limits_{0}^{6}\sqrt{((1+9t^2)')^2+((3+6t^3)')^2} dt\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i did but my answer wasn't right can u help me check the final answer again?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2ok we can check you work what did you get for (1+9t^2)'? and for (3+6t^3)'?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got 461 for the final answer, but know thats wrong what did u get?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2ok but what did you get for the derivatives of those two expressions I asked you above

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i did but just wanted to check my final answer first

freckles
 one year ago
Best ResponseYou've already chosen the best response.2is there anyway you can tell me what you got for the derivative of (1+9t^2) and (3+6t^3)

freckles
 one year ago
Best ResponseYou've already chosen the best response.2did you want me to check your problem?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2In order for me to do that I need to see where you went wrong if anywhere

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes i wanted to review the retriceer first then go over questions if possible

anonymous
 one year ago
Best ResponseYou've already chosen the best response.018t and 18t^2 is the detractive

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just like to see once i have the answer if i can work back and see my error it helps my learning

freckles
 one year ago
Best ResponseYou've already chosen the best response.2great! now inputting those in we get: \[\int\limits_{0}^{6}\sqrt{(18t)^2+(18t^2)^2} dt \\ \sqrt{18^2} \int\limits_0^6\sqrt{t^2+t^4} dt \\ 18 \int\limits_0^6 \sqrt{t^2+t^4} dt\] did you get to this part?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then do i solve from there?? because i got 29200?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2notice both terms in the sqrt( ) have a t^2 in common \[\text{ since } t>0 \text{ then we can write }\\ 18 \int\limits_0^6 \sqrt{t^2} \sqrt{1+t^2} dt \\ \\ 18 \int\limits_0^6 t \sqrt{1+t^2} dt \\ \text{ now use substituion }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have to go soon because my battery is about to die, could you share the answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0please let me know mat 1%

freckles
 one year ago
Best ResponseYou've already chosen the best response.2I haven't done the problem. I was hoping we could do it together. If u=1+t^2 then du/dt=?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2do you know power rule?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2constant rule says (1)'=0 power rule says (t^2)=?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2use wolframalpha if you just want answers
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