YanaSidlinskiy
  • YanaSidlinskiy
Answers need to be checked. DO NOT SPAM! I'M NOT JOKING!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
YanaSidlinskiy
  • YanaSidlinskiy
1.) Factor out the GCF. \[16x^7-5x^5+5x^4\]
YanaSidlinskiy
  • YanaSidlinskiy
My answer: \[x^4(16x^3-5x+5)\]
YanaSidlinskiy
  • YanaSidlinskiy
2.) Factor out the GCF:\[60x^2-12xy+28x\] My answer:\[4x(15x-3y+7)\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

YanaSidlinskiy
  • YanaSidlinskiy
3.) Factor by grouping. \[4x^2-8xy-3x+6y\] My answer: \[(4x-3)(x-2y)\]
YanaSidlinskiy
  • YanaSidlinskiy
4.) Factor:\[x^2-x-42\] My answer:\[-6,7\] >>>> I'm thinking I have this down wrong or something.. <<<<
Nnesha
  • Nnesha
you don't need to solve for x ^^^ -6 and 7 are zero (x-intercept )
anonymous
  • anonymous
4.) Is your answer the zeros?
YanaSidlinskiy
  • YanaSidlinskiy
5.) Which of the following trinomials has a greatest common factor that can be factored out first? \[100x^2+140x+49\] \[9x^2+24x+16\] \[x^2+4x+4\] \[8x^2+16x+8\]
YanaSidlinskiy
  • YanaSidlinskiy
My answer is the last one and @mathway no. My answer for number for as you can see above...
YanaSidlinskiy
  • YanaSidlinskiy
6.) Factor completely. \[1-4x^2\] My answer: \[(1-2x)^2\]
anonymous
  • anonymous
Then you're wrong. (x-6)(x+7) is not equal to the polynomial. You might want to check your signs.
YanaSidlinskiy
  • YanaSidlinskiy
Ok, thought so too!
Nnesha
  • Nnesha
6)hint apply difference of squares method
YanaSidlinskiy
  • YanaSidlinskiy
6.) Isn't that what I did??
Nnesha
  • Nnesha
difference of squares \[\huge\rm a^2-b^2 =(a\color{Red}{-}b)(a\color{reD}{+}b)\] one parentheses with negative sign and other one should be positive
Nnesha
  • Nnesha
\[\huge\rm -4x^2+1\] first take out the negative sign \[\huge\rm -(4x^2-1)\]
YanaSidlinskiy
  • YanaSidlinskiy
So it'd be: \[2x^2-1\]?
Nnesha
  • Nnesha
that is one of the factor (a-b)
YanaSidlinskiy
  • YanaSidlinskiy
Ohh! Wait. I know what I did wrong.. It'd be: \[(1-2x)(1+2x)\]
YanaSidlinskiy
  • YanaSidlinskiy
Is that right? John I see you spying ;)
Nnesha
  • Nnesha
well that's right or you can leave it as \[-(2x-1)(2x+1)\] remember we already factor out the negative sign :=)
Nnesha
  • Nnesha
thanks o^_^o
YanaSidlinskiy
  • YanaSidlinskiy
So the one is a negative then?
Nnesha
  • Nnesha
i would leave it as -(2x-1)(2x+1) which is same as (-2x+1)(2x+1) |dw:1438901505115:dw|
YanaSidlinskiy
  • YanaSidlinskiy
Ahh, ok. What about number 4? What's up with it??
YanaSidlinskiy
  • YanaSidlinskiy
Would it be (x+6)(x-7)?
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @YanaSidlinskiy 6.) Factor completely. \[1-4x^2\] My answer: \[(1-2x)^2\] \(\color{blue}{\text{End of Quote}}\) (a+b)(a+d) <-- these are factors you don't have to solve for x (x+6)(x-7) are factors x=-6,7 are zeros(x-intercept ,solutions )
Nnesha
  • Nnesha
yes that's right
johnweldon1993
  • johnweldon1993
\[\large x^2 -x - 42=0\] We have -7 and 6 as zeros...meaning \[\large (x+7)(x-6)=0\] right?
YanaSidlinskiy
  • YanaSidlinskiy
Yeah.
johnweldon1993
  • johnweldon1993
Make sure if you mean "yeah" or not...because we have 2 different answers :P
johnweldon1993
  • johnweldon1993
And that was a test :P You have it correct @YanaSidlinskiy
YanaSidlinskiy
  • YanaSidlinskiy
Ok, well for my next question.... 7.) Solve by factoring. \[b^2=32-4b\] My answer: \[-8,4\] OMG @johnweldon1993 I'M CALLING YOU ON THAT ONE!!!!! After all the struggle...... YOU JUST HAD TOO!!!!
johnweldon1993
  • johnweldon1993
I was trying to test you because you've been doing so good!! You are correct The REAL zeros are -6 and 7 So indeed \[\large (x+6)(x-7)\] is correct
johnweldon1993
  • johnweldon1993
Lol you're right, I want you confident with your answers!
YanaSidlinskiy
  • YanaSidlinskiy
LOL. I was about to go off and say that -6+7 is not -1 lol.. Omg that was a heartbeat. Say sorry hhaa;) Jkjk.. Anyways..
YanaSidlinskiy
  • YanaSidlinskiy
I've posted... #7..... Is it right?
YanaSidlinskiy
  • YanaSidlinskiy
PLEASE SAY YES haha.
Nnesha
  • Nnesha
\(\huge\color{green}{\checkmark}\)
johnweldon1993
  • johnweldon1993
Oh sorry...looked away...indeed!
YanaSidlinskiy
  • YanaSidlinskiy
Why would you look away when it's me... SUNSHINE hahha;;) Jkjk.... Anyways.. 9.) \[x^2-4x+4=0\] My answer: The equation has no real solutions..
YanaSidlinskiy
  • YanaSidlinskiy
^ I was supposed to be solving that by the quadratic formula..
johnweldon1993
  • johnweldon1993
Hmm...are you sure? You didnt get ANY zeros?
YanaSidlinskiy
  • YanaSidlinskiy
Is this a test John?
johnweldon1993
  • johnweldon1993
Lol no, a legitimate question...lets do the formula out \[\large \frac{4 \pm \sqrt{16 - 4(1)(4)}}{2}\]
YanaSidlinskiy
  • YanaSidlinskiy
\[\frac{ 4\pm \sqrt{16-16} }{ 2 }\] I tried ignoring the "-"..... Lol. Even if this is right, it'd factor out 16-16=0..
YanaSidlinskiy
  • YanaSidlinskiy
Ohh... great... Here comes the PRO.
johnweldon1993
  • johnweldon1993
No that is correct So if we have \[\large \frac{4 \pm \sqrt{0}}{2}\] Whats the square root of 0?
YanaSidlinskiy
  • YanaSidlinskiy
0..
johnweldon1993
  • johnweldon1993
Right, so it is 4 plus or minus 0 (which is just 4 in either case) divided by 2 \[\large \frac{4}{2} = ?\]
YanaSidlinskiy
  • YanaSidlinskiy
2.
johnweldon1993
  • johnweldon1993
And that is your zero :)
YanaSidlinskiy
  • YanaSidlinskiy
So, wait... x=0?
YanaSidlinskiy
  • YanaSidlinskiy
I mEAN 2=X? Hhaa.
YanaSidlinskiy
  • YanaSidlinskiy
Or more like x=2 lol...
johnweldon1993
  • johnweldon1993
There you go :) You can always check all these too...plug in 2 into your equation for 'x' and see if it comes out right
YanaSidlinskiy
  • YanaSidlinskiy
10.) If S=-16t^2+64t represents the height of a rocket, in feet, t seconds after it was fired, when will the rocket hit the ground? I got 4 seconds...
YanaSidlinskiy
  • YanaSidlinskiy
Lol, okie.
johnweldon1993
  • johnweldon1993
Ehh instead of going into a whole thing...yes correct lol
YanaSidlinskiy
  • YanaSidlinskiy
Lol, okie. Ridiculous one for the last haha;) So I'm supposed to be solving this equation using the quadratic formula... I do not know like what to do.. I mean I do but. Idk lol.. \[y^2=3y+18\]
YanaSidlinskiy
  • YanaSidlinskiy
I can do this, right? \[y^2-3y-18 = 0\]
johnweldon1993
  • johnweldon1993
Its the same thing...just using 'y' instead of 'x' But same process And yes...that is exactly what you will do!
YanaSidlinskiy
  • YanaSidlinskiy
Ok, you can have a break while I solve this... And tell me if I'm right..
johnweldon1993
  • johnweldon1993
"Makes a sandwich" :P
YanaSidlinskiy
  • YanaSidlinskiy
LOL.
YanaSidlinskiy
  • YanaSidlinskiy
6?
johnweldon1993
  • johnweldon1993
...and... remember the quadratic formula always gives you 2 answers
YanaSidlinskiy
  • YanaSidlinskiy
(6,-6)
YanaSidlinskiy
  • YanaSidlinskiy
*-3
johnweldon1993
  • johnweldon1993
Not quite... \[\large \frac{3\pm \sqrt{9 - 4(1)(-18)}}{2}\] \[\large \frac{3\pm \sqrt{9 + 72}}{2}\] \[\large \frac{3 \pm \sqrt{81}}{2}\] Ahh there you go...you got it The answers are 6 and -3
YanaSidlinskiy
  • YanaSidlinskiy
So, (6,-3)?
johnweldon1993
  • johnweldon1993
Just dont write it like that...it is not a coordinate Just y = 6 and y = -3 are solutions to this equation
YanaSidlinskiy
  • YanaSidlinskiy
|dw:1438903906614:dw|
johnweldon1993
  • johnweldon1993
Lol <3
YanaSidlinskiy
  • YanaSidlinskiy
Okie, thanks again. I gotta go cuz college closes in 30 minutes and that's where I'm at haha. So I gotta go home rn..
johnweldon1993
  • johnweldon1993
Of course :) have fun!

Looking for something else?

Not the answer you are looking for? Search for more explanations.