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1.) Factor out the GCF. \[16x^7-5x^5+5x^4\]

My answer: \[x^4(16x^3-5x+5)\]

2.) Factor out the GCF:\[60x^2-12xy+28x\]
My answer:\[4x(15x-3y+7)\]

3.) Factor by grouping. \[4x^2-8xy-3x+6y\]
My answer: \[(4x-3)(x-2y)\]

you don't need to solve for x ^^^ -6 and 7 are zero (x-intercept )

4.) Is your answer the zeros?

My answer is the last one and @mathway no. My answer for number for as you can see above...

6.) Factor completely.
\[1-4x^2\]
My answer: \[(1-2x)^2\]

Then you're wrong. (x-6)(x+7) is not equal to the polynomial. You might want to check your signs.

Ok, thought so too!

6)hint apply difference of squares method

6.) Isn't that what I did??

\[\huge\rm -4x^2+1\] first take out the negative sign
\[\huge\rm -(4x^2-1)\]

So it'd be: \[2x^2-1\]?

that is one of the factor
(a-b)

Ohh! Wait. I know what I did wrong.. It'd be: \[(1-2x)(1+2x)\]

Is that right? John I see you spying ;)

thanks o^_^o

So the one is a negative then?

i would leave it as -(2x-1)(2x+1)
which is same as (-2x+1)(2x+1)
|dw:1438901505115:dw|

Ahh, ok. What about number 4? What's up with it??

Would it be (x+6)(x-7)?

yes that's right

\[\large x^2 -x - 42=0\]
We have -7 and 6 as zeros...meaning
\[\large (x+7)(x-6)=0\]
right?

Yeah.

Make sure if you mean "yeah" or not...because we have 2 different answers :P

And that was a test :P
You have it correct @YanaSidlinskiy

Lol you're right, I want you confident with your answers!

I've posted... #7..... Is it right?

PLEASE SAY YES haha.

\(\huge\color{green}{\checkmark}\)

Oh sorry...looked away...indeed!

^ I was supposed to be solving that by the quadratic formula..

Hmm...are you sure?
You didnt get ANY zeros?

Is this a test John?

Ohh... great... Here comes the PRO.

No that is correct
So if we have
\[\large \frac{4 \pm \sqrt{0}}{2}\]
Whats the square root of 0?

0..

And that is your zero :)

So, wait... x=0?

I mEAN 2=X? Hhaa.

Or more like x=2 lol...

Lol, okie.

Ehh instead of going into a whole thing...yes correct lol

I can do this, right? \[y^2-3y-18 = 0\]

Ok, you can have a break while I solve this... And tell me if I'm right..

"Makes a sandwich" :P

LOL.

...and... remember the quadratic formula always gives you 2 answers

(6,-6)

*-3

So, (6,-3)?

|dw:1438903906614:dw|

Lol <3

Of course :) have fun!