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YanaSidlinskiy
 one year ago
Answers need to be checked. DO NOT SPAM! I'M NOT JOKING!
YanaSidlinskiy
 one year ago
Answers need to be checked. DO NOT SPAM! I'M NOT JOKING!

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YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.21.) Factor out the GCF. \[16x^75x^5+5x^4\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2My answer: \[x^4(16x^35x+5)\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.22.) Factor out the GCF:\[60x^212xy+28x\] My answer:\[4x(15x3y+7)\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.23.) Factor by grouping. \[4x^28xy3x+6y\] My answer: \[(4x3)(x2y)\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.24.) Factor:\[x^2x42\] My answer:\[6,7\] >>>> I'm thinking I have this down wrong or something.. <<<<

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2you don't need to solve for x ^^^ 6 and 7 are zero (xintercept )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04.) Is your answer the zeros?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.25.) Which of the following trinomials has a greatest common factor that can be factored out first? \[100x^2+140x+49\] \[9x^2+24x+16\] \[x^2+4x+4\] \[8x^2+16x+8\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2My answer is the last one and @mathway no. My answer for number for as you can see above...

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.26.) Factor completely. \[14x^2\] My answer: \[(12x)^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then you're wrong. (x6)(x+7) is not equal to the polynomial. You might want to check your signs.

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Ok, thought so too!

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.26)hint apply difference of squares method

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.26.) Isn't that what I did??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2difference of squares \[\huge\rm a^2b^2 =(a\color{Red}{}b)(a\color{reD}{+}b)\] one parentheses with negative sign and other one should be positive

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm 4x^2+1\] first take out the negative sign \[\huge\rm (4x^21)\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2So it'd be: \[2x^21\]?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2that is one of the factor (ab)

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Ohh! Wait. I know what I did wrong.. It'd be: \[(12x)(1+2x)\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Is that right? John I see you spying ;)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2well that's right or you can leave it as \[(2x1)(2x+1)\] remember we already factor out the negative sign :=)

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2So the one is a negative then?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2i would leave it as (2x1)(2x+1) which is same as (2x+1)(2x+1) dw:1438901505115:dw

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Ahh, ok. What about number 4? What's up with it??

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Would it be (x+6)(x7)?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @YanaSidlinskiy 6.) Factor completely. \[14x^2\] My answer: \[(12x)^2\] \(\color{blue}{\text{End of Quote}}\) (a+b)(a+d) < these are factors you don't have to solve for x (x+6)(x7) are factors x=6,7 are zeros(xintercept ,solutions )

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0\[\large x^2 x  42=0\] We have 7 and 6 as zeros...meaning \[\large (x+7)(x6)=0\] right?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Make sure if you mean "yeah" or not...because we have 2 different answers :P

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0And that was a test :P You have it correct @YanaSidlinskiy

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Ok, well for my next question.... 7.) Solve by factoring. \[b^2=324b\] My answer: \[8,4\] OMG @johnweldon1993 I'M CALLING YOU ON THAT ONE!!!!! After all the struggle...... YOU JUST HAD TOO!!!!

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0I was trying to test you because you've been doing so good!! You are correct The REAL zeros are 6 and 7 So indeed \[\large (x+6)(x7)\] is correct

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Lol you're right, I want you confident with your answers!

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2LOL. I was about to go off and say that 6+7 is not 1 lol.. Omg that was a heartbeat. Say sorry hhaa;) Jkjk.. Anyways..

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2I've posted... #7..... Is it right?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2PLEASE SAY YES haha.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\(\huge\color{green}{\checkmark}\)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Oh sorry...looked away...indeed!

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Why would you look away when it's me... SUNSHINE hahha;;) Jkjk.... Anyways.. 9.) \[x^24x+4=0\] My answer: The equation has no real solutions..

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2^ I was supposed to be solving that by the quadratic formula..

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Hmm...are you sure? You didnt get ANY zeros?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Is this a test John?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Lol no, a legitimate question...lets do the formula out \[\large \frac{4 \pm \sqrt{16  4(1)(4)}}{2}\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ 4\pm \sqrt{1616} }{ 2 }\] I tried ignoring the ""..... Lol. Even if this is right, it'd factor out 1616=0..

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Ohh... great... Here comes the PRO.

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0No that is correct So if we have \[\large \frac{4 \pm \sqrt{0}}{2}\] Whats the square root of 0?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Right, so it is 4 plus or minus 0 (which is just 4 in either case) divided by 2 \[\large \frac{4}{2} = ?\]

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0And that is your zero :)

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2So, wait... x=0?

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2I mEAN 2=X? Hhaa.

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Or more like x=2 lol...

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0There you go :) You can always check all these too...plug in 2 into your equation for 'x' and see if it comes out right

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.210.) If S=16t^2+64t represents the height of a rocket, in feet, t seconds after it was fired, when will the rocket hit the ground? I got 4 seconds...

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Ehh instead of going into a whole thing...yes correct lol

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Lol, okie. Ridiculous one for the last haha;) So I'm supposed to be solving this equation using the quadratic formula... I do not know like what to do.. I mean I do but. Idk lol.. \[y^2=3y+18\]

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2I can do this, right? \[y^23y18 = 0\]

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Its the same thing...just using 'y' instead of 'x' But same process And yes...that is exactly what you will do!

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Ok, you can have a break while I solve this... And tell me if I'm right..

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0"Makes a sandwich" :P

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0...and... remember the quadratic formula always gives you 2 answers

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Not quite... \[\large \frac{3\pm \sqrt{9  4(1)(18)}}{2}\] \[\large \frac{3\pm \sqrt{9 + 72}}{2}\] \[\large \frac{3 \pm \sqrt{81}}{2}\] Ahh there you go...you got it The answers are 6 and 3

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Just dont write it like that...it is not a coordinate Just y = 6 and y = 3 are solutions to this equation

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2dw:1438903906614:dw

YanaSidlinskiy
 one year ago
Best ResponseYou've already chosen the best response.2Okie, thanks again. I gotta go cuz college closes in 30 minutes and that's where I'm at haha. So I gotta go home rn..

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Of course :) have fun!
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