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anonymous
 one year ago
PLEASE SOMEONE HELP ITS AN SOS!!!
WILL MEDAL AND FAN
Find the distance between these points.
C(0, 4), T(6, 3)
√(37)
√(85)
√(109)
anonymous
 one year ago
PLEASE SOMEONE HELP ITS AN SOS!!! WILL MEDAL AND FAN Find the distance between these points. C(0, 4), T(6, 3) √(37) √(85) √(109)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A parallelogram whose vertices have coordinates R(1, 1), S(6, 1), T(8, 5), and U(3, 3) has a shorter diagonal of ___ . 5 √(13) √(97)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the distance between these points. W(6, 8), X(6, 8) 20 10 √8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the other endpoint of a line segment with one endpoint at (3, 5) and whose midpoint is (5, 2). (7, 2) (1, 7/2) (13, 1)

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1The distance is figured using the pythagorean theorem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ive never heard of that

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1(0,4) and (6,3) dw:1438902675608:dw

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1you can form a right triangle to get the components of a right triangle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) C&({\color{red}{ 0}}\quad ,&{\color{blue}{ 4}})\quad % (c,d) T&({\color{red}{ 6}}\quad ,&{\color{blue}{ 3}}) \end{array}\qquad % distance value d = \sqrt{({\color{red}{ x_2}}{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}{\color{blue}{ y_1}})^2}\)

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1Right, that is just memorizing the formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that how i do it using foil?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1If you know how to get to it, more likely to remember even if you forget the formulas

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is way to complicated

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1That forms a right triangle, with the property d^2 = (side1)^2 + (side2)^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its going way over my head

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1solving for Distance d, you get what @jdoe0001 typed above

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but still really confused

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1\[distance = \sqrt{(\Delta x)^2 + (\Delta y)^2}\] Distance is square root of the sum of the difference in x coordinates and the difference in y coordinates of the two points

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0um i dont get it still but thank you sooo much for your trouble

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1(0,4) and (6 , 3) \[distance = \sqrt{(6  0)^2 + (3  4)^2} = \sqrt{36 + 49} = \sqrt{85}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh so it was how i thought. I dont know why but for some reason its harder then it should be

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so all i do is foil pretty much right?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1i was just explaining what the distance formula comes from. ha sorry

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1no, no Foil. You just put the numbers in and calculate it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well guess i dont get it

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1I guess all you have to take note of is, if you given 2 points (x , y) and (x1 , y1) The distance between them is calculated by.. \[distance = \sqrt{(x  x1)^2+(yy1)^2}\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1\[distance = \sqrt{(6  0)^2 + (3  4)^2} = \sqrt{(6)^2+(7)^2 } = \sqrt{85}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh isee what u did there
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