The two dot plots below show the heights of some sixth graders and some seventh graders: The mean absolute deviation (MAD) for the first set of data is 1.2 and the MAD for the second set of data is 1.7. Approximately how many times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders? (Round all values to the tenths place.) 1.2 1.4 2.4 2.8 i think it is 1.4 @jim_thompson5910

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The two dot plots below show the heights of some sixth graders and some seventh graders: The mean absolute deviation (MAD) for the first set of data is 1.2 and the MAD for the second set of data is 1.7. Approximately how many times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders? (Round all values to the tenths place.) 1.2 1.4 2.4 2.8 i think it is 1.4 @jim_thompson5910

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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i think it is B @jim_thompson5910

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Other answers:

still thinking
I'm not sure but I'm thinking 1.7/1.2 = 1.41666666666667, so it looks like you are correct
The table below shows the data for a random sample of fish that were collected from and later released into a lake: Type of Fish Catfish Grass Carp Bluegill Number of Fish 52 61 87 How many bluegills are estimated to be present if a sample of 800 fish is collected from the lake? 148 174 244 348 D, yes? @jim_thompson5910
correct 52+61+87 = 200 87/200 = 0.435 0.435*800 = 348
A researcher posts a magazine advertisement offering $30 in exchange for participation in a short study. The researcher accepts the first three people who respond to the advertisement. Which of the following statements is true about the sample? It is not a valid sample because it is not a random sample of the population. It is a valid sample because the first three people were selected to participate. It is a valid sample because money was offered to participants. It is not a valid sample because it is only a short study. A? @jim_thompson5910
yeah it's not random and probably biased based on how payment is involved
Melissa wants to know if the number of words on a page in her geography book is generally more than the number of words on a page in her math book. She takes a random sample of 25 pages in each book, then calculates the mean, median, and mean absolute deviation for the 25 samples of each book. Mean Median Mean Absolute Deviation Geography 48.9 41 9.2 Math 34.5 44 1.9 She claims that because the mean number of words on each page in the geography book is greater than the mean number of words on each page in the math book, the geography book has more words per page. Based on the data, is this a valid inference? Yes, because the mean is larger in the geography book No, because the mean is larger in the geography book No, because there is a lot of variability in the geography book data Yes, because there is a lot of variability in the geography book data @jim_thompson5910
Juliet conducted a survey to find the favorite type of book of the students at her school. She asked 20 students from her class what their favorite type of book is. Juliet concludes that short stories is the favorite type of book of the students in her school because 80% of the students in her class like short stories. Use at least two sentences to explain why Juliet's sample may not be valid. Juliet's sample may not be valid because her class is not a random sample. The 20 students in her class do not represent the entire school. @jim_thompson5910
Agreed. She is better off placing all of the names in school in a hat or something, then randomly picking out the names.
Below are the data collected from two random samples of 500 American students on the number of hours they spend in school per day (rounded to the nearest hour): Number of hours in school per day 4 5 6 7 8 Sample A: Number of students 70 100 125 135 70 Sample B: Number of students 80 90 120 125 85 Meg concludes that students spend a mean of 7 hours in school each day. Tara thinks the mean is 6 hours. Who is correct—Meg or Tara? Explain your answer in two or three sentences.
what did you get
607
:(
how did you get that
multiplied options by the hours spent in school, added them then divided
plz help
still thinking
I think I have it, one sec
ok I think you forgot to divide by 100 instead of 607 it should be 6.07 so Tara is right
The table below shows the size of nine families selected at random from two neighborhoods in a large city: Family Size (in number of people) Neighborhood A 4 4 5 5 5 5 5 5 6 Neighborhood B 6 5 5 4 4 3 4 2 4 Which neighborhood appears to have a bigger family size? Explain your answer using two or three sentences. @jim_thompson5910
find the mean of each data set
can u help me with that?
Add up all the values in row 1, then divide that sum by 9. What do you get?
hang on a sec
A: 4.89 B: 4.11
so a?
correct
The dot plots below show the ages of students belonging to two groups of painting classes: Based on visual inspection, which group most likely has a lower mean age of painting students? Explain your answer using two or three sentences.
Probably Group A because there is less variability than Group B. The variability for Group A is also closer to the smaller numbers on the number line. this is what i put @jim_thompson5910
B is more spread out and that pulls the mean to the right. B has a larger mean
the question says lower mean @jim_thompson5910
so that means A has a lower mean
was i correct then?
Clara surveyed the students at her school to find out if they like pies and/or sandwiches. The results of her survey are shown in the two-way table below: Like Pies Do Not Like Pies Total Like Sandwiches 25 43 68 Do Not Like Sandwiches 26 6 32 Total 51 49 100 If a student does not like sandwiches, what is the probability that student also does not like pies? 81.3% 26.0% 23.1% 18.8% @jim_thompson5910
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how many total do not like sandwiches?
was my other question correct? and 32
yeah the other one was correct
how many don't like sandwiches and dont' like pies?
81
no, 6
I'll brb
wait
what do i do with this question?
so 6/32 = 0.1875 = 18.75% is the answer
The graph below shows Jamie's science scores versus the number of hours spent doing science homework: What will most likely be Jamie's approximate science score if he does science homework for 7 hours a week? 53 points 61 points 72 points 83 points @jim_thompson5910
you forgot the graph
oh sorry lol
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i think it would be 61
I'm getting a score between 70 and 80
The graph below shows the relationship between the number of months different students practiced tennis and the number of matches they won: Part A: What is the approximate y-intercept of the line of best fit and what does it represent? (5 points) Part B: Write the equation for the line of best fit in the slope-intercept form and use it to predict the number of matches that could be won after 13 months of practice. (5 points)
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thx. my last problem for this exam is above @jim_thompson5910

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