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anonymous
 one year ago
The two dot plots below show the heights of some sixth graders and some seventh graders:
The mean absolute deviation (MAD) for the first set of data is 1.2 and the MAD for the second set of data is 1.7. Approximately how many times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders? (Round all values to the tenths place.)
1.2
1.4
2.4
2.8
i think it is 1.4
@jim_thompson5910
anonymous
 one year ago
The two dot plots below show the heights of some sixth graders and some seventh graders: The mean absolute deviation (MAD) for the first set of data is 1.2 and the MAD for the second set of data is 1.7. Approximately how many times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders? (Round all values to the tenths place.) 1.2 1.4 2.4 2.8 i think it is 1.4 @jim_thompson5910

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think it is B @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1still thinking

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I'm not sure but I'm thinking 1.7/1.2 = 1.41666666666667, so it looks like you are correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The table below shows the data for a random sample of fish that were collected from and later released into a lake: Type of Fish Catfish Grass Carp Bluegill Number of Fish 52 61 87 How many bluegills are estimated to be present if a sample of 800 fish is collected from the lake? 148 174 244 348 D, yes? @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1correct 52+61+87 = 200 87/200 = 0.435 0.435*800 = 348

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A researcher posts a magazine advertisement offering $30 in exchange for participation in a short study. The researcher accepts the first three people who respond to the advertisement. Which of the following statements is true about the sample? It is not a valid sample because it is not a random sample of the population. It is a valid sample because the first three people were selected to participate. It is a valid sample because money was offered to participants. It is not a valid sample because it is only a short study. A? @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yeah it's not random and probably biased based on how payment is involved

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Melissa wants to know if the number of words on a page in her geography book is generally more than the number of words on a page in her math book. She takes a random sample of 25 pages in each book, then calculates the mean, median, and mean absolute deviation for the 25 samples of each book. Mean Median Mean Absolute Deviation Geography 48.9 41 9.2 Math 34.5 44 1.9 She claims that because the mean number of words on each page in the geography book is greater than the mean number of words on each page in the math book, the geography book has more words per page. Based on the data, is this a valid inference? Yes, because the mean is larger in the geography book No, because the mean is larger in the geography book No, because there is a lot of variability in the geography book data Yes, because there is a lot of variability in the geography book data @jim_thompson5910

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Juliet conducted a survey to find the favorite type of book of the students at her school. She asked 20 students from her class what their favorite type of book is. Juliet concludes that short stories is the favorite type of book of the students in her school because 80% of the students in her class like short stories. Use at least two sentences to explain why Juliet's sample may not be valid. Juliet's sample may not be valid because her class is not a random sample. The 20 students in her class do not represent the entire school. @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Agreed. She is better off placing all of the names in school in a hat or something, then randomly picking out the names.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Below are the data collected from two random samples of 500 American students on the number of hours they spend in school per day (rounded to the nearest hour): Number of hours in school per day 4 5 6 7 8 Sample A: Number of students 70 100 125 135 70 Sample B: Number of students 80 90 120 125 85 Meg concludes that students spend a mean of 7 hours in school each day. Tara thinks the mean is 6 hours. Who is correct—Meg or Tara? Explain your answer in two or three sentences.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what did you get

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1how did you get that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0multiplied options by the hours spent in school, added them then divided

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1still thinking

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I think I have it, one sec

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1ok I think you forgot to divide by 100 instead of 607 it should be 6.07 so Tara is right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The table below shows the size of nine families selected at random from two neighborhoods in a large city: Family Size (in number of people) Neighborhood A 4 4 5 5 5 5 5 5 6 Neighborhood B 6 5 5 4 4 3 4 2 4 Which neighborhood appears to have a bigger family size? Explain your answer using two or three sentences. @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1find the mean of each data set

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u help me with that?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Add up all the values in row 1, then divide that sum by 9. What do you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The dot plots below show the ages of students belonging to two groups of painting classes: Based on visual inspection, which group most likely has a lower mean age of painting students? Explain your answer using two or three sentences.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Probably Group A because there is less variability than Group B. The variability for Group A is also closer to the smaller numbers on the number line. this is what i put @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1B is more spread out and that pulls the mean to the right. B has a larger mean

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the question says lower mean @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so that means A has a lower mean

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Clara surveyed the students at her school to find out if they like pies and/or sandwiches. The results of her survey are shown in the twoway table below: Like Pies Do Not Like Pies Total Like Sandwiches 25 43 68 Do Not Like Sandwiches 26 6 32 Total 51 49 100 If a student does not like sandwiches, what is the probability that student also does not like pies? 81.3% 26.0% 23.1% 18.8% @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1how many total do not like sandwiches?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0was my other question correct? and 32

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yeah the other one was correct

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1how many don't like sandwiches and dont' like pies?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what do i do with this question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@campbell_st @Preetha

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so 6/32 = 0.1875 = 18.75% is the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The graph below shows Jamie's science scores versus the number of hours spent doing science homework: What will most likely be Jamie's approximate science score if he does science homework for 7 hours a week? 53 points 61 points 72 points 83 points @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you forgot the graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think it would be 61

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I'm getting a score between 70 and 80

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The graph below shows the relationship between the number of months different students practiced tennis and the number of matches they won: Part A: What is the approximate yintercept of the line of best fit and what does it represent? (5 points) Part B: Write the equation for the line of best fit in the slopeintercept form and use it to predict the number of matches that could be won after 13 months of practice. (5 points)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thx. my last problem for this exam is above @jim_thompson5910
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