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anonymous
 one year ago
please help,
anonymous
 one year ago
please help,

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0let x be an arbitary nonempty set and p: X*X> R be discrete metric on x, defined by p(x,y)= k^2  4 if x \[\neq y\] and 0 if x=y ... obtain the possible values of k

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@zzr0ck3r , @Kainui , @oldrin.bataku

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@zzr0ck3r , @Kainui , @oldrin.bataku

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0what is the first rule of being a metric?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1I think if \(x\neq y\) then the distance between them \(\neq 0\) and = k^2 4 Moreover, the distance is never negative, hence k^2 4 >0 and k<2 or k >2

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0The discrete metric just puts the same distance between all points (think integers). 1st rule of metric club is that we only obtain non negative values. i.e. \[K^24\ge 0\]

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1@zzr0ck3r cannot be =0, right?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1but at that time, x =y while we are considering \(x\neq y\)

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1Because it is a piece wise function. dw:1438908728253:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1when k =2, p(x,y) =0 we must use the second piece of the function to work out. Like if it is dw:1438908882357:dw 0 stays at only 1 part of the function. Can't stay in both.

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0So we have \(K^24>0\).

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0I deleted my stuff as not to confuse @GIL.ojei

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok sir, thanks . are the values K<2 or k>2????

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0please is that correct sirs?
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