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anonymous
 one year ago
please help I will fan and medal
A quadratic equation is shown below:
9x2 − 16x + 60 = 0
Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work.
Part B: Solve 4x2 + 8x − 5 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used.
anonymous
 one year ago
please help I will fan and medal A quadratic equation is shown below: 9x2 − 16x + 60 = 0 Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. Part B: Solve 4x2 + 8x − 5 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used.

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DanJS
 one year ago
Best ResponseYou've already chosen the best response.0the radicand is the part underneath the root in the quadratic formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so how would I answer part a

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0the equation given has the standard form ax^2 + bx + c = 0, what is the radicand?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0The quadratic formula is \[x = \frac{ b \pm \sqrt{b^24ac} }{ 2a }\] the radicand under the root tells you if you have real or complex solutions depending if it is positive or negative value

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0b^2  4*a*c = (16)^2  4 * 9 * 60 = 1904

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0a negative under a square root has imaginary solutions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay the as part says to Describe the solution(s) to the equation by just determining the radicand. the solutions are imaginary but how would I show my work?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0Show the calculation i did above, turns out negative

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0For B) not sure what appropriate method means, if it works , that is good, you may be able to factor it, but you can always apply that quadratic formula
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