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Last question I need help on for tonight.

Mathematics
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1 Attachment
Part A: Which is the correct net for the prism? Explain your answer. (2 points) Part B: Write the measurements of Sides AB, BC, and CD of the correct net. (4 points) Part C: What is the surface area of the prism? Show your work. (4 points)
i believe net a is the correct net for the prism btw

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yes, fold it up in your mind
Yes its net A
How would i go about doing part B?
yes, then write the corresponding measurements on it
like, AB is 3 in
CD = 9.4 in BC you have to use pythagorean theorem to get
THe sides of that right triangle are 3 and 4, so the hypotenuse side is root(3^2 + 4^2) = root 25 = 5 It is a 3-4-5 triangle
oh, the 5 is on the drawing, i missed it
so bc=5
yea
how do i find the area?
3*9.4*5*1/2?
total up the areas of every side...
3 rectangles and 2 triangles Area Rectangle = Length x Width Area Triangle = 0.5 x base x height
so 37.6 is the area of the rectangle and 15 is the area of the triangle
Rectangles: 9.4*4 + 9.4*5 + 9.4*3 = .. Triangles: 0.5 * 4 * 3 + 0.5 * 4 * 3
add all those up for the total surface area
0.5 is 1/2 right?
yea
i got 112.8 and 6
so the total area is 118.8
yeah the area of 1 triangle is 6, but there are 2
add 6 more ,, and you are good
130.8
112.8 + 12 = 124.8 in^2 total surface area
oh yes i forgot to start from 112.8

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