HELP is anyone in connexus!!? geometry B and can help

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HELP is anyone in connexus!!? geometry B and can help

Mathematics
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i did that polygon similarity one you closed
@DanJS thank you Dan mind helping me again
sure

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I need to find the value of x and y but im confused as to how
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first thing i see is just to set up 2 pythagorean theorems, and solve for x and y
maybe, might be too much work
im just confused im not sure how to get it
Triangle ABC and Triangle BDC are similar, they both have 3 of the same angles
since both have a right angle and the same marked angle, so the third angle is the same
so you can do ratios of the sides like last prob
\[\frac{ AB }{ BD } = \frac{ BC }{ AC } = \frac{ BC }{ DC }\]
\[\frac{ 5 }{ 3 } = \frac{ y }{ x+4 } = \frac{ y }{ x }\]
You can solve that for x and y
can you show me how to?
yes kinda
Not gonna lie im a bit lost by that
sorry that is false, i messed up
oh lol okay
ok, i just used two pythagorean theorems, and got x = 9/4 and y=15/4
Solving 5^2 + y^2 = (4+x)^2 and 3^2 + x^2 = y^2
did it on my calculator, no work
Hmmm thank you dan :)
welcome
In a right triangle, if an altitude is drawn to the hypotenuse, then all three triangles are similar. This is the situation with this problem. Start with triangle ABC. Since angle ABC is a right angle, triangle ABC is a right triangle. Segment BD is the altitude of triangle ABC drawn to the hypotenuse of triangle ABC. That means that triangles ABC, ADB, and BDC are similar triangles. Once you know the triangles are similar, then the lengths of corresponding sides are proportional, so you can write these two proportions: \(\dfrac{AB}{BC} = \dfrac{AD}{BD} \) and \(\dfrac{AD}{BD} = \dfrac{BD}{DC} \) Replacing all segments by their given lengths, x, and y, you get: \(\dfrac{5}{y} = \dfrac{4}{3} \) and \(\dfrac{4}{3} = \dfrac{3}{x} \) \(4y = 15\) \(4x = 9\) \(y = \dfrac{15}{4} = 3.75\) \(x = \dfrac{9}{4} = 2.25\)

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