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anonymous
 one year ago
What is the arc length of a circle that has a 7centimeter radius and a central angle that is 40 degrees? Use 3.14 for π and round your answer to the nearest hundredth.
anonymous
 one year ago
What is the arc length of a circle that has a 7centimeter radius and a central angle that is 40 degrees? Use 3.14 for π and round your answer to the nearest hundredth.

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DanJS
 one year ago
Best ResponseYou've already chosen the best response.140 out of 360 is the ratio of the circumference you are looking for

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1Circumference = 2*pi*7 take 40/360 of that

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438914335003:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1to the nearest hundredth means to 2 decimal places. calculate to 3 . if the 3rd is 5 or more add 1 to the 2nd. if the 3rd is less than 5 just drop it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@DanJS Circumference=43.96 What do you mean by "take 40/360 of that"?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@triciaal I don't really understand what I'm supposed to do...

DanJS
 one year ago
Best ResponseYou've already chosen the best response.140/360 is 1/9 of the total circle

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1so you want a ninth of the circumference for a 40 degree arc

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1since you using decimals, 40/360 is about 0.11 so take 0.11 times circumference

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1the length of the arc varies with the angle complete circle = 360 degrees and the circumference is 2*pi* r set up ratio and solve for l

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438914919428:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@DanJS Thank you so much! @triciaal Yes, thanks a ton for your explanation!
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