DarkBlueChocobo
  • DarkBlueChocobo
Help with Inverse functions
Mathematics
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DarkBlueChocobo
  • DarkBlueChocobo
Help with Inverse functions
Mathematics
chestercat
  • chestercat
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DarkBlueChocobo
  • DarkBlueChocobo
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DanJS
  • DanJS
f(x) = y = 5 - 2x^3
DanJS
  • DanJS
you can simply change the x and y variables around and resolve for y, that is the inverse function

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DanJS
  • DanJS
i can explain why, if you need
DanJS
  • DanJS
x = 5 - 2y^3
DarkBlueChocobo
  • DarkBlueChocobo
So solve for y like in any like in any normal like line?-
DanJS
  • DanJS
yeah, swap x and y around, solve for y
DarkBlueChocobo
  • DarkBlueChocobo
Alright
DarkBlueChocobo
  • DarkBlueChocobo
2y^3=-x+5
DarkBlueChocobo
  • DarkBlueChocobo
-1/2x+5/2
DarkBlueChocobo
  • DarkBlueChocobo
|dw:1438919912211:dw|3
DarkBlueChocobo
  • DarkBlueChocobo
?
DanJS
  • DanJS
right, that is f^(-1)
DanJS
  • DanJS
basically just reflecting the graph over the line y=x
DarkBlueChocobo
  • DarkBlueChocobo
Alright that was actually pretty simple Thank you!
DanJS
  • DanJS
welcome

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