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anonymous
 one year ago
Solve x2 − 3x = −8
anonymous
 one year ago
Solve x2 − 3x = −8

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pooja195
 one year ago
Best ResponseYou've already chosen the best response.0a ,b , c values are \[\huge\rm Ax^2+Bx+C=0\] where a =leading coefficient b= leading coefficient c= constant term So we need to add 8 to both sides \[\huge~\rm~ x^2 − 3x+8 \] Now factor from here What numbers multiply to make 8 but add to make 3? if there are none the answer would be prime

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk what numbers multiply to 8 and add to 3

pooja195
 one year ago
Best ResponseYou've already chosen the best response.0Then clearly there is not solution :) reread what i wrote are you given options?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no solution isnt an option

pooja195
 one year ago
Best ResponseYou've already chosen the best response.0What are the options?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Um I don't know how to right them out

pooja195
 one year ago
Best ResponseYou've already chosen the best response.0I havent learned "i" yet.... @UsukiDoll

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Use the quadratic formula.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0HUH?! O_O! that was random

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0yeah use quadratics on this equation... use discriminant formula b^24ac to see if we have a perfect square or not perfect square  we can factor not a perfect square  use quadratic formula

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge~\rm~ x^2 − 3x+8 \] where a = 1, b = 3, and c = 8 plug it into the discriminant formula which is b^24ac \[\LARGE (3)^24(1)(8) \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[\LARGE (3)^24(1)(8) \] \[\LARGE 932 = 23 \] not a perfect square and a negative... ok looks like we're going to have complex roots.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0now we solved the b^24ac already so that makes the quadratic formula a bit easier \[\LARGE \frac{ b \pm \sqrt{b^24ac}}{2a}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0since a = 1, b = 3, and c = 8 \[\LARGE \frac{ (3) \pm \sqrt{23}}{2}\] negatives aren't allowed in the radical...so we write an i which stands for imaginary. \[\LARGE \frac{ 3 \pm \sqrt{23}i}{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer would be b?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0wait... I haven't looked at that portion yet.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay ill try to get it on something else

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0finally got through to it.. it is the second choice.
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