DarkBlueChocobo
  • DarkBlueChocobo
Help with exponential functions
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
DarkBlueChocobo
  • DarkBlueChocobo
1 Attachment
zzr0ck3r
  • zzr0ck3r
Bah I lost it all...damn internet
DarkBlueChocobo
  • DarkBlueChocobo
so we will have ab^5=96

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

zzr0ck3r
  • zzr0ck3r
\(\dfrac{ab^7}{ab^5}=\dfrac{384}{96}\) Solve for \(b\) and then use that to find \(a\).
DarkBlueChocobo
  • DarkBlueChocobo
I don't know why that sounds more difficult than it feels like it will be. How would you find B? seperate it or like fill 0 in for a?
zzr0ck3r
  • zzr0ck3r
\(\dfrac{ab^7}{ab^5}=\dfrac{384}{96}\implies b^2 = 4\implies b = 2\) not very hard at all
zzr0ck3r
  • zzr0ck3r
\(\dfrac{ab^7}{ab^5}=\dfrac{384}{96}\implies \dfrac{\cancel{a}b^7}{\cancel{a}b^5}=\dfrac{384}{96}\implies \dfrac{b^7}{b^5}=\dfrac{384}{96}\implies b^{7-5}=\dfrac{384}{96}\\\implies b^2 = \dfrac{384}{96}\implies b^2 = 4\implies b = 2\)
DarkBlueChocobo
  • DarkBlueChocobo
Oh so a's cancel out and you get left with b's then b^2 = 4 meaning b=2 then cause 384/96 is 4
zzr0ck3r
  • zzr0ck3r
\(\dfrac{ab^7}{ab^5}=\dfrac{384}{96}\implies \dfrac{\cancel{a}b^7}{\cancel{a}b^5}=\dfrac{384}{96}\implies \dfrac{b^7}{b^5}=\dfrac{384}{96}\implies b^{7-5}=\dfrac{384}{96}\\\implies b^2 = \dfrac{384}{96}\implies b^2 = 4\implies b = 2\)
UsukiDoll
  • UsukiDoll
maybe now if b =2 we can grab a ?
zzr0ck3r
  • zzr0ck3r
We don't consider \(b=-2\) because we are told \(b\) is positive. Now we need \(a\), and so we use \(b\) \(f(5) = 96 \implies a(2)^5 = 96 \implies a32=96 \implies a=3\)
zzr0ck3r
  • zzr0ck3r
So \(f(x) = 3(2)^x\)
DarkBlueChocobo
  • DarkBlueChocobo
so a2^5=96 2*2*2*2*2 =32 a= 96/32=3 a=3
zzr0ck3r
  • zzr0ck3r
It's just like when you had two linear equations in two variables and you used the addition method. Except instead of adding the equations, we divide them. The \(a, b>0\) gives that we will never divide by zero
UsukiDoll
  • UsukiDoll
let me try ... just this once f(x) = ab^x so when f(5) = 96 so x = 5 and b = 2 f(5) =a2^5 96=32a 3 = a
zzr0ck3r
  • zzr0ck3r
correct @DarkBlueChocobo

Looking for something else?

Not the answer you are looking for? Search for more explanations.