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DarkBlueChocobo
 one year ago
Help with exponential functions
DarkBlueChocobo
 one year ago
Help with exponential functions

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zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3Bah I lost it all...damn internet

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1so we will have ab^5=96

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3\(\dfrac{ab^7}{ab^5}=\dfrac{384}{96}\) Solve for \(b\) and then use that to find \(a\).

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1I don't know why that sounds more difficult than it feels like it will be. How would you find B? seperate it or like fill 0 in for a?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3\(\dfrac{ab^7}{ab^5}=\dfrac{384}{96}\implies b^2 = 4\implies b = 2\) not very hard at all

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3\(\dfrac{ab^7}{ab^5}=\dfrac{384}{96}\implies \dfrac{\cancel{a}b^7}{\cancel{a}b^5}=\dfrac{384}{96}\implies \dfrac{b^7}{b^5}=\dfrac{384}{96}\implies b^{75}=\dfrac{384}{96}\\\implies b^2 = \dfrac{384}{96}\implies b^2 = 4\implies b = 2\)

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1Oh so a's cancel out and you get left with b's then b^2 = 4 meaning b=2 then cause 384/96 is 4

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3\(\dfrac{ab^7}{ab^5}=\dfrac{384}{96}\implies \dfrac{\cancel{a}b^7}{\cancel{a}b^5}=\dfrac{384}{96}\implies \dfrac{b^7}{b^5}=\dfrac{384}{96}\implies b^{75}=\dfrac{384}{96}\\\implies b^2 = \dfrac{384}{96}\implies b^2 = 4\implies b = 2\)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0maybe now if b =2 we can grab a ?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3We don't consider \(b=2\) because we are told \(b\) is positive. Now we need \(a\), and so we use \(b\) \(f(5) = 96 \implies a(2)^5 = 96 \implies a32=96 \implies a=3\)

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1so a2^5=96 2*2*2*2*2 =32 a= 96/32=3 a=3

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3It's just like when you had two linear equations in two variables and you used the addition method. Except instead of adding the equations, we divide them. The \(a, b>0\) gives that we will never divide by zero

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0let me try ... just this once f(x) = ab^x so when f(5) = 96 so x = 5 and b = 2 f(5) =a2^5 96=32a 3 = a

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3correct @DarkBlueChocobo
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