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anonymous

  • one year ago

Given that BDFHJ ~ QSUWY, what is YQ? A. 76 B. 78 C. 87 D. 96

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  1. anonymous
    • one year ago
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    i was thinking a @izuru

  2. anonymous
    • one year ago
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    Look at which sides correspond to one another.

  3. anonymous
    • one year ago
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    60,65?

  4. anonymous
    • one year ago
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    One corresponding side is JH~QS. The proportion is \[\frac{ 66 }{ 72 }\]. Also, another side of corresponding sides are JB~YQ. What's the proportion for JB~YQ?

  5. anonymous
    • one year ago
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    so its C

  6. anonymous
    • one year ago
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    @izuru ?

  7. anonymous
    • one year ago
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    guys??

  8. anonymous
    • one year ago
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    guys come on are you there @izuru @AaronAndyson

  9. anonymous
    • one year ago
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    @mathway @mathstudent55

  10. mathstudent55
    • one year ago
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    From the statement of similarity of two polygons, you can tell which sides are corresponding sides.

  11. anonymous
    • one year ago
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    ok so i'm getting C

  12. mathstudent55
    • one year ago
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    Using these letters --------> We know these sides are corresponding \(\color{red}{BD}FHJ \sim \color{red}{QS}UWY\) -----> BD and QS \(B\color{red}{DF}HJ \sim Q\color{red}{SU}WY\) -----> DF and SU \(BD\color{red}{FH}J \sim QS\color{red}{UW}Y\) -----> FH and UW \(BDF\color{red}{HJ} \sim QSU\color{red}{WY}\) -----> HJ and WY \(\color{red}{B}DFH\color{red}{J} \sim \color{red}{Q}SUW\color{red}{Y}\) -----> BJ and QY

  13. mathstudent55
    • one year ago
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    YQ corresponds to BJ \(\dfrac{YQ}{BJ} = \dfrac{QS}{BD}\) \(\dfrac{YQ}{60} = \dfrac{72}{45}\) \(\dfrac{YQ}{60} = \dfrac{8}{5}\) \(5(YQ) = 8 \times 60\) \(YQ = 96\)

  14. anonymous
    • one year ago
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    this took way to long but thank you anyways.

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