anonymous
  • anonymous
Given that BDFHJ ~ QSUWY, what is YQ? A. 76 B. 78 C. 87 D. 96
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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anonymous
  • anonymous
http://static.k12.com/calms_media/media/1421000_1421500/1421043/1/5c8c0dadfc6c632953c6e5dd9c2749232c37c09c/MS_Alg_130924_281855.jpg
anonymous
  • anonymous
i was thinking a @izuru
anonymous
  • anonymous
Look at which sides correspond to one another.

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anonymous
  • anonymous
60,65?
anonymous
  • anonymous
One corresponding side is JH~QS. The proportion is \[\frac{ 66 }{ 72 }\]. Also, another side of corresponding sides are JB~YQ. What's the proportion for JB~YQ?
anonymous
  • anonymous
so its C
anonymous
  • anonymous
@izuru ?
anonymous
  • anonymous
guys??
anonymous
  • anonymous
guys come on are you there @izuru @AaronAndyson
anonymous
  • anonymous
@mathway @mathstudent55
mathstudent55
  • mathstudent55
From the statement of similarity of two polygons, you can tell which sides are corresponding sides.
anonymous
  • anonymous
ok so i'm getting C
mathstudent55
  • mathstudent55
Using these letters --------> We know these sides are corresponding \(\color{red}{BD}FHJ \sim \color{red}{QS}UWY\) -----> BD and QS \(B\color{red}{DF}HJ \sim Q\color{red}{SU}WY\) -----> DF and SU \(BD\color{red}{FH}J \sim QS\color{red}{UW}Y\) -----> FH and UW \(BDF\color{red}{HJ} \sim QSU\color{red}{WY}\) -----> HJ and WY \(\color{red}{B}DFH\color{red}{J} \sim \color{red}{Q}SUW\color{red}{Y}\) -----> BJ and QY
mathstudent55
  • mathstudent55
YQ corresponds to BJ \(\dfrac{YQ}{BJ} = \dfrac{QS}{BD}\) \(\dfrac{YQ}{60} = \dfrac{72}{45}\) \(\dfrac{YQ}{60} = \dfrac{8}{5}\) \(5(YQ) = 8 \times 60\) \(YQ = 96\)
anonymous
  • anonymous
this took way to long but thank you anyways.

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