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DarkBlueChocobo
 one year ago
Help with logarithims
DarkBlueChocobo
 one year ago
Help with logarithims

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DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0For the first one would you just fill in x for 0?

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0to which we would get log(10)10+3

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[\log_a(a)=1 \text{ where } a \in (0,1) \cup (1,\infty)\]

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0I am confused are you saying log10(10)=1?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2yes \[10 \in (1,\infty) \\ \text{ so } 10 \in (0,1) \cup (1,\infty) \\ \text{ so yes } \log_{10}(10)=1 \]

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0so like then we just add 3? so f(0)=4?

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0and for the second one would you just divide log(10)20/log(10)3

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0so log(3)20=x so you just seperate? and then they both have the common log(10)? im trying to udnerstand why

freckles
 one year ago
Best ResponseYou've already chosen the best response.2you can solve the equation by first taking log_10 of both sides

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[\log_{10}(20)=\log_{10}(3^x) \\ \log_{10}(20)=x \log_{10}(3) \text{ by power rule } \]

freckles
 one year ago
Best ResponseYou've already chosen the best response.2then divide both sides be log_10(3)

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0Alrights Thank you for clearing that up. Egh last night of cramming for this test

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{\log_{10}(20)}{\log_{10}(3)}=\frac{x \log_{10}(3)}{\log_{10}(3)} \\ \frac{\log_{10}(20)}{\log_{10}(3)}=x\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.2you could have chosen any log base as long as that base is a number between 0 and 1 exclusive or between 1 and infinity exclusive

freckles
 one year ago
Best ResponseYou've already chosen the best response.2maybe they want you to express in base 5 log well take log_5( ) of both side instead

freckles
 one year ago
Best ResponseYou've already chosen the best response.2just doing an example... \[20=3^x \\ \log_5(20)=\log_5(3^x) \\ \log_5(20)=x \log_5(3) \\ \frac{\log_5(20)}{\log_5(3)}=x\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.2notice that answer could be expressed as: \[x=\frac{\log_a(20)}{\log_a(3)} \text{ where } a \in (0,1) \cup (1,\infty)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.2yes equality is symmetrical if a=b then b=a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the can we say x=log3(20)?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2yes my answer will also conclude that if you put a as 3 \[x=\frac{\log_3(20)}{\log_3(3)}=\frac{\log_3(20)}{1}=\log_3(20)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can't we say x as a decimal?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2you mean approximate x ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03^1=3 3^2=9 3^3=27 so x must be between 2 and three.... and so on?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But if we are asked to find x for 4 decimal places can we find it? :(

freckles
 one year ago
Best ResponseYou've already chosen the best response.2calculator would probably be your friend

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can we find it without using it?
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