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DarkBlueChocobo

  • one year ago

Help with polynomials

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  1. DarkBlueChocobo
    • one year ago
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  2. DarkBlueChocobo
    • one year ago
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    @mathstudent55

  3. DarkBlueChocobo
    • one year ago
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    I don't understand how to find it :/

  4. sepeario
    • one year ago
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    I think you expand it and then use discriminant?

  5. DarkBlueChocobo
    • one year ago
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    Can you explain the discriminant

  6. phi
    • one year ago
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    the "roots" of a polynomial are the x values that make the polynomial zero. here you have \[ (x-4)^2 (x^2+4) = 0\] or \[ (x-4) (x-4) (x^2+4) = 0\] as you can see, if x= 4 (twice, so it is a repeated root) you get zero you would also get 0 if x^2+4=0 or \( x^2= -4 \) take the square root of both sides and you get \[ x= 2i \text{ or } x=-2i\] the 4 roots are: 4,4,+2i, -2i

  7. phi
    • one year ago
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    Statement I is true: you have two imaginary roots: 2i and -2i II is false: you do have the real root 4 III is true: you have four complex roots, namely 4,4, 2i and -2i statement III is a bit tricky, because we must recognize that pure real (like 4) and pure imaginary (like 2i) can both be categorized as complex.

  8. ali2x2
    • one year ago
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    I and III are true.

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