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AaronAndyson
 one year ago
sec^2(A) + cosec^2(A) = sec^2(A).cosec^2(A)
@michele_liano
AaronAndyson
 one year ago
sec^2(A) + cosec^2(A) = sec^2(A).cosec^2(A) @michele_liano

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have to apply these identities: \[\sec A = \frac{1}{{\cos A}},\quad \csc A = \frac{1}{{\sin A}}\]

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0have u tried to solve the expression?? try converting the terms into sin nd cos form nd then take the LCM nd solve

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1left side becomes: \[\sec A + {\left( {\csc A} \right)^2} = \frac{1}{{\cos A}} + {\left( {\frac{1}{{\sin A}}} \right)^2} = ...\] please continue

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I think that there is a typo into your original expression, please check

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1ok! so left side becomes: \[{\left( {\sec A} \right)^2} + {\left( {\csc A} \right)^2} = {\left( {\frac{1}{{\cos A}}} \right)^2} + {\left( {\frac{1}{{\sin A}}} \right)^2} = ...\]

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0ok m calling sinA = x nd cosA=y 1/y^2 +1/x^2 take LCM we get  (x^2 + y^2)/(xy)^2 we know that sin^2A+cos^2A = 1 therefore the numerator = 1 nd we r left with 1/(xy)^2 =sec^A cosec^A

AaronAndyson
 one year ago
Best ResponseYou've already chosen the best response.0sin^2(A)+cos^2(A)/cos(A)sin(A) = RHS

AaronAndyson
 one year ago
Best ResponseYou've already chosen the best response.01/sin(A)cos(A) = sec(A)cosec(A) = RHS

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1more precisely, it is: sin^2(A)+cos^2(A)/cos(A)^2 sin(A)^2 = RHS

AaronAndyson
 one year ago
Best ResponseYou've already chosen the best response.0i nedd more help *need
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