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anonymous
 one year ago
Can someone help me find the inverse of the function f(x)=2x+1/2
anonymous
 one year ago
Can someone help me find the inverse of the function f(x)=2x+1/2

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0we can rewrite your function as below: \[\Large y = 2x + \frac{1}{2}\] now solve that equation for x, what do you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Replace x to y x=2y+(1/2) 2y=x  (1/2) y=(x/2) (1/4) Inverse function is (x/2) (1/4)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0please you have to find x as a function of y

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0starting from my equation above, we get: 2x=y1/2 so x=...?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1dude I would just swap x and y and solve for y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[y=2x+\frac{ 1 }{ 2 } \rightarrow x= 2y+\frac{ 1 }{ 2 }\] now make y the subject

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0being y=f(x) and since your function admits its inverse function, then we can write: \[\Large x = {f^{  1}}\left( y \right) = \frac{1}{2}\left( {y  \frac{1}{2}} \right)\] now, if you want to change variable, namely y>x then we can write: \[\Large {f^{  1}}\left( x \right) = \frac{1}{2}\left( {x  \frac{1}{2}} \right)\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1agreez \[f(x) = 2x+ \frac{1}{2} \] \[y = 2x+ \frac{1}{2} \] \[x = 2y+ \frac{1}{2} \] \[x  \frac{1}{2} = 2y \] \[\frac{1}{2}x  \frac{1}{4} = y \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok thanks everyone I got it, you guys helped a lot! (:
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