AaronAndyson
  • AaronAndyson
Perform the indicated expression: 2tan28°tan62°
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ankit042
  • ankit042
x= 28 2tan(90-x).tan(x)= 2sin(90-x).sin(x)/cos(90-x).cos(x)
ankit042
  • ankit042
Now sin(90-x)=? cos(90-x)=?
Michele_Laino
  • Michele_Laino
we have this: \[\Large \tan 90 = \tan \left( {28 + 62} \right) = \frac{{\tan 28 + \tan 62}}{{1 - \tan 28\tan 62}}\]

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Jhannybean
  • Jhannybean
Ahh, I didn't know you could combine it :)
Michele_Laino
  • Michele_Laino
now, since tan90= infinity, we have to request that: \[\Large 1 - \tan 28\tan 62 = 0\]
Michele_Laino
  • Michele_Laino
therefore: \[\Large 2 - 2\tan 28\tan 62 = 0\]
AaronAndyson
  • AaronAndyson
thanks
AaronAndyson
  • AaronAndyson
1/sec^2(36) - cot^(54) =
AaronAndyson
  • AaronAndyson
^ help me with that

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