Evaluate fourth root of 9 multiplied by square root of 9 over the fourth root of 9 to the power of 5.

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Evaluate fourth root of 9 multiplied by square root of 9 over the fourth root of 9 to the power of 5.

Mathematics
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i give medals :)
here are the choices 9 to the power of negative 1 over 2 9 to the power of negative 1 over 4 9 92
\(\color{blue}{\text{Originally Posted by}}\) @x.curlsss i give medals :) \(\color{blue}{\text{End of Quote}}\) i prefer chocolates

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lol but can you help me
alright \[\huge\rm \frac{ \sqrt[4]{9} \times \sqrt{9} }{ \sqrt[4]{9^5}} \] like this ?
what does the 4 at the top mean
4th root
oh ok
alright so you can convert root to exponent exponent rule \[\huge\rm \sqrt[m]{x^n} = x^ \frac{ n }{ m }\]
m= root number n= exponent of base under the root
9 4/5 right?
n over m not m over n
|dw:1438952130246:dw|
i need to go :( but which one of the choices would it be
A or B or maybe D or C
how would you convert \[\sqrt[4]{9^1} = ???\] to exponent form ?
idk thats why I'm confused :/
|dw:1438952454421:dw| just apply the exponent look at the drawing just like i convertd 4th root of 9^5 to 9 to the 5/4 power
|dw:1438952562345:dw|
9 1/4?
yes right and square root of 9 = ?
3
or 81 ?
yea now you have \[\huge\rm \frac{ 9^\frac{ 1 }{ 4 } \times 3 }{ 9^\frac{ 5 }{ 4 } }\] there are same bases at the numerator and t the denominator you need to apply quotient exponent rule \[\large\rm \frac{ x^m }{ x^n }=x^{m-n}\]
81?
would it be A ?
how did you get that >? ;)

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