The height of a projectile that has been launched upward can be determined by finding the sum of the product of one-half of the object’s acceleration and t2, the product of the object’s initial velocity and t, and the object’s initial height, where t represents the number of seconds after the object has been launched. An object’s acceleration can be assumed to be -32 ft/s2, which is the acceleration due to gravity. c. If a projectile is launched into the air from the ground with an initial velocity of 192 feet per second, how long after launch will the projectile be at a height of 320 feet? S

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The height of a projectile that has been launched upward can be determined by finding the sum of the product of one-half of the object’s acceleration and t2, the product of the object’s initial velocity and t, and the object’s initial height, where t represents the number of seconds after the object has been launched. An object’s acceleration can be assumed to be -32 ft/s2, which is the acceleration due to gravity. c. If a projectile is launched into the air from the ground with an initial velocity of 192 feet per second, how long after launch will the projectile be at a height of 320 feet? S

Mathematics
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I love physics
Is this kinematics?
Use one of the formulas from your formula sheet and plug the values in.

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Other answers:

I think it's the one with h(final)=1/2a*t^2+vt+h(initial)
Do you understand the formula?
yes thank you

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