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I ONLY NEED PART C IGIVE MEDALS :)

help please?

20 year value,
n = 20, put that in both of your functions from part B

can you show me how to solve it

what are your functions from part b ?

1300+300n
1300+300n* 1.3n

f(n) = 1000(1.3)^n

Each next term is the previous multiplied by 1.3

Option 2) Each term increases by the same amount over the previous term, it is always 300 more

f(n) = (starting value) + n*(common difference)
f(n) = 1000 + 300*n

so i use this to solve for the difference
right?

1) f(n) = 1000(1.3)^n
2) f(n) = 1000 + 300*n
yep, put n=20 in both options and calculate the values

do i subtract both of the answers i get for the answer

you dont have to, just compare them

option 1 should be way larger

yes it was that you so much :)

*thank

welcome