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anonymous
 one year ago
Belinda wants to invest $1000. The table below shows the value of her investment under two different options for three different years:
Number of years 1 2 3
Option 1 (amount in dollars) 1300 1690 2197
Option 2 (amount in dollars) 1300 1600 1900
Part A: What type of function, linear or exponential, can be used to describe the value of the investment after a fixed number of years using option 1 and option 2? Explain your answer. (2 points)
Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years. (4 points)
Part C: Beli
anonymous
 one year ago
Belinda wants to invest $1000. The table below shows the value of her investment under two different options for three different years: Number of years 1 2 3 Option 1 (amount in dollars) 1300 1690 2197 Option 2 (amount in dollars) 1300 1600 1900 Part A: What type of function, linear or exponential, can be used to describe the value of the investment after a fixed number of years using option 1 and option 2? Explain your answer. (2 points) Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years. (4 points) Part C: Beli

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part C: Belinda wants to invest in an option that would help to increase her investment value by the greatest amount in 20 years. Will there be any significant difference in the value of Belinda's investment after 20 years if she uses option 2 over option 1? Explain your answer, and show the investment value after 20 years for each option. (4 points)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I ONLY NEED PART C IGIVE MEDALS :)

DanJS
 one year ago
Best ResponseYou've already chosen the best response.120 year value, n = 20, put that in both of your functions from part B

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you show me how to solve it

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1what are your functions from part b ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01300+300n 1300+300n* 1.3n

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1hmm The first option is exponential form (1000)*(r)^n The second option is linear form 1000 + n*d have to figure what r and d are

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1Option 1) THe function looks like (initial investment)*(r)^n \[f(n) = 1000*(r)^n\] r is the common ratio of consecutive terms 1300/1000 = 1.3 or 1690/1300 = 1.3 or 2197/1690 = 1.3 r is 1.3

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1Each next term is the previous multiplied by 1.3

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1Option 2) Each term increases by the same amount over the previous term, it is always 300 more

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1f(n) = (starting value) + n*(common difference) f(n) = 1000 + 300*n

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i use this to solve for the difference right?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.11) f(n) = 1000(1.3)^n 2) f(n) = 1000 + 300*n yep, put n=20 in both options and calculate the values

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do i subtract both of the answers i get for the answer

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1you dont have to, just compare them

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1option 1 should be way larger

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes it was that you so much :)
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