## anonymous one year ago Which of the following is the first incorrect step? Step 4 Step 6 Step 7 Step 8

1. anonymous

Step 1 ax2 + bx + c = 0 Step 2 ax2 + bx = − c Step 3 x2 + b over a times x equals negative c over a Step 4 x2 + b over a times x plus b squared over 4 times a squared equals negative c over a plus b squared over 4 times a squared Step 5 x2 + b over a times x plus b squared over 4 times a squared equals negative 4 multiplied by a multiplied by c, all over 4 multiplied by a squared plus b squared over 4 times a squared Step 6 the square of the quantity x plus b over 2 times a equals b squared minus 4 multiplied by a multiplied by c, all over 4 times a squared Step 7 x plus b over 2 times a equals plus or minus square root of the quantity b squared minus 4 times a times c over 4 times a squared equals plus or minus square root of b squared minus 4 times a times c, all divided by 4 times a Step 8 x = −negative b over 2 times a plus or minus square root of b squared minus 4 times a times c, all divided by 2 times a Step 9 x = negative b plus or minus square root of b squared minus 4 times a times c, all divided by 2 times a

2. anonymous

Plz help someone FAN AND MEDAL

3. anonymous

its better if we put em to equation mode lol

4. anonymous

Yeah ik but teachers these days I swear they give them like this to me ._.

5. anonymous

6. anonymous

lol irk XD

7. anonymous

step 4 looks like this $\left[\begin{matrix}x^2+b \\ x+b^2 \\ 4a^2 \end{matrix}\right] = \left[\begin{matrix}-c \\ a+b^2 \\ 4a^2 \end{matrix}\right]$

8. anonymous

idk how to 3 tier the fraction so i used matrix

9. anonymous

brb

10. anonymous

Did you get the answer to this?

11. anonymous

that question successfully confused me

12. anonymous

back and yes it confused me too BLAME FLVS

13. anonymous

lol I did this question on a test yesterday

14. anonymous

Well then can you check your grade book and tell me what you got? XD

15. anonymous

Yeah hold on

16. anonymous

Step 4 is what I got

17. anonymous

XD ok thanks everyone for all

18. anonymous

You are welcome

19. anonymous

step 5 looks like $\left[\begin{matrix}x^2+b \\ x+b^2 \\ 4a^2 \end{matrix}\right]=\left[\begin{matrix}-4ac \\ 4a^2+b^2 \\ 4a^2 \end{matrix}\right]$

20. anonymous

Ok

21. anonymous

i have no idea about step 6...dat english

22. anonymous

mostly just write em down and you can form that fraction

23. anonymous

lol and this is supposedly Algebra 1 ._.