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anonymous

  • one year ago

Quadrilateral BCDE is inscribed inside a circle as shown below. Write a proof showing that angles C and E are supplementary.

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @rishavraj

  3. anonymous
    • one year ago
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    i really need some help on this ive seen others like this question but the answer never made sense

  4. midhun.madhu1987
    • one year ago
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    Since the 4 vertices of the quadrilateral BCDE lies on the circle...hence it is a Cyclic Quadrilateral.. The sum of the opposite angles of a cyclic quadrilateral is 180. Do you want the proof of this theorem??

  5. anonymous
    • one year ago
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    yes please

  6. midhun.madhu1987
    • one year ago
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    http://nrich.maths.org/1310

  7. anonymous
    • one year ago
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    could you explain it? @midhun.madhu1987

  8. midhun.madhu1987
    • one year ago
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    |dw:1438966898875:dw|

  9. midhun.madhu1987
    • one year ago
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    Angle BOD = 2 Angle BAD Angle BAD = (1/2) Angle BOD ----(1) Angle DOB = 2 Angle BCD Angle BCD = (1/2) Angle BCD ----(2) Adding both equations (1) and (2) Angle BAD + Angle BCD = (1/2) Angle BOD + (1/2) Angle BCD = (1/2) (Angle BOD + Angle BCD) = (1/2) * 360 = 180 Hope you got it

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