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mathmath333
 one year ago
Counting problem
mathmath333
 one year ago
Counting problem

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \color{black}{\begin{align}& \normalsize \text{The number of ways in which a Chairman and a ViceChairman can be chosen}\hspace{.33em}\\~\\ & \normalsize \text{from amongst a group of 12 persons assuming}\hspace{.33em}\\~\\ & \normalsize \text{that one person can not hold more than}\hspace{.33em}\\~\\ & \normalsize \text{one position.}\hspace{.33em}\\~\\ \end{align}}\)

ali2x2
 one year ago
Best ResponseYou've already chosen the best response.1this is off a google book xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know C notation?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4First choose chairman, there are \(12\) ways of doing this. After that, choose vicechairman, there are \(11\) ways of doing this. So both can be done together in \(12\times 11\) ways

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Using C notation:\(^{12}C_2\times2\)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1what does it mean by \(\large \color{black}{\begin{align} & \normalsize \text{assuming that one person can not hold more}\hspace{.33em}\\~\\ & \normalsize \text{ than one position is ?}\hspace{.33em}\\~\\ \end{align}}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4Notice that the order in which you chose the ppl didnt matter here, end of the day all you care about is who were picked for chairman and vicechairman, not the order in which you pick them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It says one person can't be president and vice at the same time!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you @ganeshie8 and @mathmath333 for meddling me!!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4:) notice that \(^{12}C_2*2 = 12*11\) which is same as the number of different strings of length \(2\) formed by picking letters from a set of \(12\) different letters. @mathmath333

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1also notice that \(\large ^{12}P_{2}=132\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4Yep, all those interpretations are equivalent

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4we have \[\large ^nP_r~ ~=~~ ^nC_r * r!\]
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