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mathmath333

  • one year ago

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align} & \normalsize \text{Find the number of ways or rearranging the word}\quad \Large \rm INSTITUTE\hspace{.33em}\\~\\ \end{align}}\)

  2. anonymous
    • one year ago
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    This is a permutation

  3. anonymous
    • one year ago
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    9*8*7*6*5*4*3*2*1=

  4. anonymous
    • one year ago
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    That's your answer bro

  5. mathmath333
    • one year ago
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    u mean \(\large 9!\)

  6. anonymous
    • one year ago
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    yeah I do

  7. phi
    • one year ago
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    you have to account for repeated letters

  8. anonymous
    • one year ago
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    That's why it's 9 exclamation happy mathy day

  9. mathmath333
    • one year ago
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    hmm that is given as wrong

  10. rhr12
    • one year ago
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    Opps!! Idk what is that.

  11. freckles
    • one year ago
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    \[\frac{ \text{ total number of letters }!}{\text{ repetitions of letter i}!}\] where i can be a,b,c,....z

  12. freckles
    • one year ago
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    for example if we had the word ball it would be 4!/2!

  13. freckles
    • one year ago
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    or if we had the word mississippi it would be \[\frac{11!}{4! \cdot 4! \cdot 2!}\]

  14. freckles
    • one year ago
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    where one of those 4's account for the amount of s the other 4 account for the amount of i and where 2 account for the amount of p

  15. mathmath333
    • one year ago
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    (9/2*3)!

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