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anonymous
 one year ago
Solve the triangle.
A = 50°, b = 13, c = 6
anonymous
 one year ago
Solve the triangle. A = 50°, b = 13, c = 6

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes I get that but how do I find my missing pieces

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0You can use the law of sines or cosines

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't get how to do that I'm going virtual school and I need someone to walk me step by step

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0http://www.mathwarehouse.com/trigonometry/lawofcosinesformulaexamples.php

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0\[a^2 = 6^2 + 13^2  2(6)(13)*\cos(50)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't have a calculator except my phone so when I do it, I don't get any of my answer choices

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0you get side a from that one, then you can use law of sines to get the last 2 angles \[\frac{ \sin(A) }{ a } = \frac{ \sin(B) }{ b } = \frac{ \sin(C) }{ c }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is there anyway you can calculate that because my phone doesn't get me the correct answer

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0a^2 = 36 + 169  156*(0.6428) a^2 = 104.7 a = about 10.2

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ \sin(50) }{ 10.2 }=\frac{ \sin(B) }{ 13 }\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0THe last angle is 180  the other 2
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