anonymous
  • anonymous
Solve the triangle. A = 50°, b = 13, c = 6
Mathematics
jamiebookeater
  • jamiebookeater
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DanJS
  • DanJS
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anonymous
  • anonymous
Yes I get that but how do I find my missing pieces
DanJS
  • DanJS
You can use the law of sines or cosines

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anonymous
  • anonymous
I don't get how to do that I'm going virtual school and I need someone to walk me step by step
DanJS
  • DanJS
http://www.mathwarehouse.com/trigonometry/law-of-cosines-formula-examples.php
DanJS
  • DanJS
\[a^2 = 6^2 + 13^2 - 2(6)(13)*\cos(50)\]
anonymous
  • anonymous
I don't have a calculator except my phone so when I do it, I don't get any of my answer choices
DanJS
  • DanJS
you get side a from that one, then you can use law of sines to get the last 2 angles \[\frac{ \sin(A) }{ a } = \frac{ \sin(B) }{ b } = \frac{ \sin(C) }{ c }\]
anonymous
  • anonymous
Is there anyway you can calculate that because my phone doesn't get me the correct answer
DanJS
  • DanJS
a^2 = 36 + 169 - 156*(0.6428) a^2 = 104.7 a = about 10.2
DanJS
  • DanJS
\[\frac{ \sin(50) }{ 10.2 }=\frac{ \sin(B) }{ 13 }\]
DanJS
  • DanJS
B= about 77.5 degrees
DanJS
  • DanJS
THe last angle is 180 - the other 2

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