## anonymous one year ago Solve the triangle. A = 50°, b = 13, c = 6

1. DanJS

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2. anonymous

Yes I get that but how do I find my missing pieces

3. DanJS

You can use the law of sines or cosines

4. anonymous

I don't get how to do that I'm going virtual school and I need someone to walk me step by step

5. DanJS
6. DanJS

$a^2 = 6^2 + 13^2 - 2(6)(13)*\cos(50)$

7. anonymous

I don't have a calculator except my phone so when I do it, I don't get any of my answer choices

8. DanJS

you get side a from that one, then you can use law of sines to get the last 2 angles $\frac{ \sin(A) }{ a } = \frac{ \sin(B) }{ b } = \frac{ \sin(C) }{ c }$

9. anonymous

Is there anyway you can calculate that because my phone doesn't get me the correct answer

10. DanJS

a^2 = 36 + 169 - 156*(0.6428) a^2 = 104.7 a = about 10.2

11. DanJS

$\frac{ \sin(50) }{ 10.2 }=\frac{ \sin(B) }{ 13 }$

12. DanJS

B= about 77.5 degrees

13. DanJS

THe last angle is 180 - the other 2