anonymous
  • anonymous
will medal and fan!!! A base of a parallelogram is on the x-axis and the origin is located at the left endpoint of that base. Three consecutive vertices are (h, j), (0, 0), and (k, 0), where h > 0. How many units to the right of a vertical line through (k, 0) must the fourth vertex be? h 2h k + h
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
The x-axis and y-axis are lines of symmetry for a square. If one of its vertices has coordinates ( a, b), then the vertice opposite it is ( a, -b) (- a, -b) (- a, b)
DanJS
  • DanJS
The base of that parallelogram is from (0,0) to (k,0)
anonymous
  • anonymous
ok..

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anonymous
  • anonymous
so what do i do now
DanJS
  • DanJS
(h, j ) is the upper left point from consecutive terms To get the upper right point, you stay at the same y-coordinate, and move right the same length as the base, k units
anonymous
  • anonymous
i still nit understanding
anonymous
  • anonymous
not
DanJS
  • DanJS
|dw:1438970086465:dw|
anonymous
  • anonymous
would it be 2h? just asking
DanJS
  • DanJS
The base is k units long... So the top must also be k units long the y coordinate stays the same value
DanJS
  • DanJS
|dw:1438970314909:dw|
anonymous
  • anonymous
so its H+k?
DanJS
  • DanJS
yep
anonymous
  • anonymous
yay!!
anonymous
  • anonymous
thank you!!!!!!!! what about the second one?
DanJS
  • DanJS
oh, wait
anonymous
  • anonymous
i think its A but im not to sure,,
DanJS
  • DanJS
it is h, sorry, they want to know the horizontal distance from (k , 0) to ( k + h , j )
anonymous
  • anonymous
ohhhhhhhhhhh okay
DanJS
  • DanJS
|dw:1438970527607:dw|
anonymous
  • anonymous
:)
anonymous
  • anonymous
is the second one A? thats what i got
DanJS
  • DanJS
|dw:1438970646681:dw|
anonymous
  • anonymous
oh .. i get it.........thx!!!!
DanJS
  • DanJS
welcome

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