mathmath333
  • mathmath333
Counting question
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
mathmath333
  • mathmath333
\(\large \color{black}{\begin{align} & \normalsize \text{How many numbers lying between 100 and 1000 }\hspace{.33em}\\~\\ & \normalsize \text{can be formed with the digits 0, 1, 2, 3, 4, 5,}\hspace{.33em}\\~\\ & \normalsize \text{ if the repetition of the digits is not allowed?}\hspace{.33em}\\~\\ \end{align}}\)
xapproachesinfinity
  • xapproachesinfinity
I'm in counting principles
xapproachesinfinity
  • xapproachesinfinity
not good *

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mathmath333
  • mathmath333
lol what u want to say
ParthKohli
  • ParthKohli
Let's just take three-digit numbers (1000 won't be counted anyway). _ _ _ Whenever repetition is not allowed, we reduce the number of choices by 1 for each subsequent blank. The leftmost blank allows 1, 2, 3, 4, 5 so 5 numbers. The second blank allows 4 numbers but zero is also included, so 5 numbers. The last blank allows 4 numbers. The total number is 5 * 5 * 4 = 100.

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