Photon336
  • Photon336
A scientist measures the freezing point depression of a 0.1m sodium nitrate solution. He uses the ideal van't hoff factor for the calculation of the ideal freezing point depression. the observed freezing point depression is.
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Photon336
  • Photon336
A. not measurable, because the solution did not freeze. B. lower than the theoretical. C. less than the change in the boiling point. D. higher than the theoretical.
Photon336
  • Photon336
first and foremost, let's assume that if we have some electrolyte XY in solution. I'm guessing that our van hoff factor i shows us how many moles of ions were produced by that solution. but what it assumes to my knowledge is that there isn't any interaction between molecules. you see i though that interactions between the ions might possibly explain why the van hoff factor measured experimentally would be lower than your ideal one. \[XY --> X ^{+} + Y ^{-}\]
Photon336
  • Photon336
|dw:1438971657651:dw|

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Photon336
  • Photon336
\[iK _{b}\Delta T\]
Photon336
  • Photon336
I thought it would be lower but I believe that was wrong. I thought maybe if the ions interact somehow maybe that would lower the i and lower the delta T. not sure. your thoughts are welcome
Photon336
  • Photon336
Said B. but it's wrong
Rushwr
  • Rushwr
is it A?/
Rushwr
  • Rushwr
@Photon336 I haven't tried all this neither learnt in school . But was trying with what I knew !
abb0t
  • abb0t
Freezing point depression is teh process when u add a solute to a solvent to decreases the freezing point of the solvent.
abb0t
  • abb0t
I would have guessed D.
Photon336
  • Photon336
@abb0t that's the correct answer
Photon336
  • Photon336
@Rushwr the answer is D.
Rushwr
  • Rushwr
@Photon336 I have no idea LOL! SOrry for that
Photon336
  • Photon336
So i would guess that since i is lower the van hoff factor, it doesn't freeze at a lower temperature as it should
Photon336
  • Photon336
so the temperature would be higher than the theoretical
Photon336
  • Photon336
Because of two reasons i guess it's like colligative properties; the first thing that i guess because the ions pair in solution, I think of it as there being fewer solute molecules in solution, so the freezing point would be higher than what's expected.
Photon336
  • Photon336
any thoughts are welcome
abb0t
  • abb0t
Nice. And yes, it is based on colligative properties.
Photon336
  • Photon336
will post another. question guys
Rushwr
  • Rushwr
okaaai

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