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anonymous
 one year ago
Derive the equation of the parabola with a focus at (0, 1) and a directrix of y = −1.
anonymous
 one year ago
Derive the equation of the parabola with a focus at (0, 1) and a directrix of y = −1.

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zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1I think I remember you asking this yesterday? :O

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Our Vertex is always equidistant from our focus and directrix, ya? So that puts us at 0,0

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Umm from here... we can either do it the long way... or use that nice shortcut formula.. im trying to remember what it looks like..

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Here is that shortcut that I was thinking of: \[\large\rm (x  h)^2 = 4p (y  k)\]Where our vertex is the point (h,k), and p is the distance between the focus and vertex.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes thank you i did ask yesterday but i had trouble at the end and couldnt find a :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0h and k i got as 0, 0

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm (x0)^2=4p(y0)\]\[\large\rm x^2=4py\]Ok good. let's solve for y,\[\large\rm y=\frac{1}{4p}x^2\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1And then, what is the value of p? The distance from the vertex up to the focus?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wouldnt it be 2? from 1 to 1? or no

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438975963650:dwNo that would be 2p :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438976050358:dwis this the focus? at 0,1

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438976120582:dwyes :) i want to know the distance from here to here from the VERTEX to the FOCUS. not from the DIRECTRIX silly :)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm y=\frac{1}{4p}x^2 \qquad\to\qquad y=\frac{1}{4\cdot1}x^2\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Yayyy team, we did it! \c:/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i got it now thank you soo much
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