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hybrik

  • one year ago

A point T on a segment with endpoints D(1, 4) and F(7, 1) partitions the segment in a 2:1 ratio. Find T.

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  1. hybrik
    • one year ago
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    I did my work, but it doesn't seem right.

  2. anonymous
    • one year ago
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    What did you get?

  3. hybrik
    • one year ago
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    (5.33,3.33)

  4. anonymous
    • one year ago
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    Basically, you subtract y1 and y (and x1 and x) then divide it by the ratio 2:1, 2+1=3. So you divide it by 3. |dw:1438973308499:dw|

  5. hybrik
    • one year ago
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    Oh, I added instead. I did 8/3 and 5/3

  6. anonymous
    • one year ago
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    So for x, I got 2. Now what you want to do is subtract 2 from 7 (x2).

  7. anonymous
    • one year ago
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    lol i typed x1 and x instead of x2 and x1; hope you didn't get confused :D

  8. hybrik
    • one year ago
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    So you get -1, for Y, then add 4-1 (3) to it?

  9. anonymous
    • one year ago
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    And for y, since the ratio is 2:1, then you have to add -1 to 4 two times. So, it would be 4+(-1)+(-1). For me, I'd go to the closest point, F then subtract -1. 1-(-1)=. It's still the same though.

  10. hybrik
    • one year ago
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    So the point would be 2,2

  11. hybrik
    • one year ago
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    Yes, no?

  12. anonymous
    • one year ago
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    \(\color{#0cbb34}{\text{Originally Posted by}}\) @mathway So for x, I got 2. Now what you want to do is subtract 2 from 7 (x2). \(\color{#0cbb34}{\text{End of Quote}}\) The x-value is wrong. What is 7-2?

  13. hybrik
    • one year ago
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    cinco

  14. anonymous
    • one year ago
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    correcto

  15. hybrik
    • one year ago
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    5,2

  16. anonymous
    • one year ago
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    yes :)

  17. hybrik
    • one year ago
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    Let me see if I graph it it looks, reasonable.

  18. hybrik
    • one year ago
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    Yep, its reasonable

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