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anonymous

  • one year ago

PLEASE HELP ME I AM SO LOST I HAVE NO IDEA HOW TO APPLY THIS OR WHERE TO START: Two forces with magnitudes of 150 and 75 pounds act on an object at angles of 30° and 150° respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer. So i started off trying to find the resultant vector by adding these: 150cos(30)x +150sin(30)y 75cos(150)x + 75sin(150)y

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  1. welshfella
    • one year ago
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    |dw:1438981308566:dw|

  2. anonymous
    • one year ago
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    .

  3. welshfella
    • one year ago
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    |dw:1438981420279:dw|

  4. welshfella
    • one year ago
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    resolve horizontally F1 = 150 cos 30 - 75 cos 30 resolve vertically F2 = 150 sin 30 + 75 sin 30

  5. welshfella
    • one year ago
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    |dw:1438981651618:dw|

  6. welshfella
    • one year ago
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    you now have to find the resultant of F1 and F2

  7. welshfella
    • one year ago
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    what do you get for F1 and F2?

  8. welshfella
    • one year ago
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    yoy can find this resultant using pythagoras |dw:1438982214222:dw|

  9. welshfella
    • one year ago
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    R is the magnitude of the resultant force and x = arctan (F2/F1) is the direction

  10. welshfella
    • one year ago
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    gotta go Hope this has helped

  11. Loser66
    • one year ago
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    Still need help?

  12. anonymous
    • one year ago
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    |dw:1438995269233:dw|

  13. anonymous
    • one year ago
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    F1 = <150 cos 30, 150 sin 30> F2= <75 cos 150 , 75 sin 150> Resultant = F1 + F2 = < 150 cos 30 + 75 cos 150 , 150 sin 30 + 75 sin 150> = <64.95, 112.5> Magnitude of resultant = √( 64.95^2 + 112.5^2) = 129.9 Angle = arctan (112.5 / 64.95) ~ 60.0 degrees

  14. Loser66
    • one year ago
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    |dw:1438996035190:dw|

  15. Loser66
    • one year ago
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    |dw:1438996074837:dw|

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