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anonymous

  • one year ago

Points J (5,2) and K (-2,-5) are two vertices of a isosceles triangle. If L is the third vertex and has a y-coordinate of 4, what is the x-coordinate of L?

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  1. campbell_st
    • one year ago
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    well there seem to be 2 options for this question 1. the sides LJ = KL so make the vertex L =(x, 4) and use the distance formula the 2nd choice would be JK is one of the equal sides... I think the 1st option is the easier

  2. anonymous
    • one year ago
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    how do i do that

  3. anonymous
    • one year ago
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    @campbell_st

  4. campbell_st
    • one year ago
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    ok... so let L be the point (x, 4) so use the distance formula LJ \[d_{LJ} = \sqrt{(x - 5)^2 +(4 - 2)^2}\] and LK \[d_{LK} = \sqrt{(x + 2)^2 +(4 + 5)^2}\] equate the distances... since the triangle is isosceles and sqaure both sides and you get \[(x -5)^2 +(4 -2)^2 = (x +2)^2 + (4+5)^2\] so now you can distribute, simplify then solve for x hope it makes sense

  5. anonymous
    • one year ago
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    hey can we use the pythagoream theorum instead because we don't use the distance formula

  6. anonymous
    • one year ago
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    ??

  7. campbell_st
    • one year ago
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    the distance formula is pythagoras. theorem |dw:1438981802265:dw|

  8. campbell_st
    • one year ago
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    now looking at pythagoras |dw:1438981887808:dw| you can find LJ and LK in terms of pythagoras then solve for x that's all I did above.

  9. anonymous
    • one year ago
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    how do i use the pythagorean therorum with this

  10. campbell_st
    • one year ago
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    I already have by equating the lengths and squaring both sides of the equation you get \[(x -5)^2 + (4 -2)^2 = (x + 2)^2 +(4 + 5)^2\] start by simplifying this equation

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