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anonymous

  • one year ago

Solve the following system of equations. y = x^2 + 3 y = x + 5

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  1. anonymous
    • one year ago
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    I know that the coeffecients must be opposite..

  2. lυἶცἶ0210
    • one year ago
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    Since y =x+5 you could plug that into the first equation: \(\large y=\color{green}{x^2+3} \) \(\large y=\color{red}{x+5}\) \(\Large \color{red}{x+5}=\color{green}{x^2+3}\) Now solve

  3. campbell_st
    • one year ago
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    so you are looking for the points of intersection, so you can equate them \[x + 5 = x^2 + 3\] if you rewrite the equation you get \[x^2 - x - 2 = 0\] this can be solved by factoring

  4. anonymous
    • one year ago
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    okay, would it be 1 and 1? not sure

  5. campbell_st
    • one year ago
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    so find the factors of -2 that add to -1 the larger factor is negative and the smaller is positive

  6. campbell_st
    • one year ago
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    when you get the solutions for x, substitute them into either equation to find the corresponding y values... remember the solutions are points (x,y)

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