## redheadangel one year ago A cylinder’s radius is reduced to 2/5 its original size and the height is quadrupled. How has the volume of the cylinder changed?

I think I know the answer but I just wanted a second opinion

@Peaches15

@CausticSyndicalist

4. anonymous

well if you let radius = 1 and height = h the volume of the cylinder is $V = \pi \times1^1\times h = \pi h$ so if the radius becomes 2/5 and height becomes 4h then $V = \pi \times (\frac{2}{5})^2 \times 4h$ or $V=\frac{16}{25} \pi h$