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redheadangel

  • one year ago

A cylinder’s radius is reduced to 2/5 its original size and the height is quadrupled. How has the volume of the cylinder changed?

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  1. redheadangel
    • one year ago
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    I think I know the answer but I just wanted a second opinion

  2. redheadangel
    • one year ago
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    @Peaches15

  3. redheadangel
    • one year ago
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    @CausticSyndicalist

  4. anonymous
    • one year ago
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    well if you let radius = 1 and height = h the volume of the cylinder is \[V = \pi \times1^1\times h = \pi h\] so if the radius becomes 2/5 and height becomes 4h then \[V = \pi \times (\frac{2}{5})^2 \times 4h\] or \[V=\frac{16}{25} \pi h\]

  5. redheadangel
    • one year ago
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    Thank you soooo much!!

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