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HelloKitty17

  • one year ago

What are the exact solutions of x2 - 3x - 5 = 0? x = the quantity of negative 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 11 all over 2 x = the quantity of negative 3 plus or minus the square root of 11 all over 2

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  1. HelloKitty17
    • one year ago
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    @Mehek14

  2. OregonDuck
    • one year ago
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    Since the given polynomial is not factorabl, we apply quadratic formula x = (-b ± √(b² - 4ac))/2a, along with ax² + bx + c = 0: a = 1 b = -3 c = -5 x = (3 ± √((-3)² - 4*1*-5))/2 ==> (3 ± √(9 + 20))/2 ==> (3 ± √29)/2

  3. HelloKitty17
    • one year ago
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    Since the given polynomial is not factorabl, we apply quadratic formula x = (-b ± √(b² - 4ac))/2a, along with ax² + bx + c = 0: a = 1 b = -3 c = -5 x = (3 ± √((-3)² - 4*1*-5))/2 ==> (3 ± √(9 + 20))/2 ==> (3 ± √29)/2 I hope this helps!

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